Answer:
41.74 m/s
Explanation:
The energy used to draw the bowstring = the kinetic energy of the arrow.
Fd = 1/2mv²................................ Equation 1
Where F = force, d = distance move string, m = mass of the arrow, v = speed of the arrow.
make v the subject of the equation
v = √(2Fd/m)...................... Equation 2
Given: F = 201 N, m = 0.3 kg, d = 1.3 m.
Substitute into equation 2
v = √(2×201×1.3/0.3)
v = √(1742)
v = 41.74 m/s.
Hence the arrow leave the bow with a speed of 41.74 m/s
Answer:
Explanation:
circumference of the tyre = 2πr = 2 x 3.14 x 0.26 = 1.6328m
76000km = 76000000m
no of revolutions required
= 76000000/1.6328 = 46546 revolutions.
Answer:
Explanation:
We shall apply law of conservation of momentum during the collision of ball A and B .
Total momentum before collision of A and B = .35 x 10 = 3.5 kg m/s
Let the velocity of B after collision be v .
Total momentum after collision = .35 x 2 + .35v
According to law of conservation of momentum
.35 x 2 + .35v = 3.5
.35 v = 2.8
v = 8 m /s .
The direction of B will be same as direction of A .
1 W = 1 J/s
Watt<span> is the unit of measure for power .
</span><span>
</span>Joule is the unit of measure for the energy and the second is the unit of measure for time.
