Using these Elements. Here would be the 4 ionic compounds.
CaF2
VF5
CaS
V2S5
Answer: The value of 
for the half-cell reaction is 0.222 V.
Explanation:
Equation for solubility equilibrium is as follows.
Its solubility product will be as follows.
![K_{sp} = [Ag^{+}][Cl^{-}]](https://tex.z-dn.net/?f=K_%7Bsp%7D%20%3D%20%5BAg%5E%7B%2B%7D%5D%5BCl%5E%7B-%7D%5D)
Cell reaction for this equation is as follows.
Reduction half-reaction: 
, 
Oxidation half-reaction: 
, 
= ?
Cell reaction: 
So, for this cell reaction the number of moles of electrons transferred are n = 1.
Solubility product,
= 
Therefore, according to the Nernst equation
![E_{cell} = E^{o}_{cell} - \frac{0.0592 V}{n} log \frac{[AgCl]}{[Ag^{+}][Cl^{-}]}](https://tex.z-dn.net/?f=E_%7Bcell%7D%20%3D%20E%5E%7Bo%7D_%7Bcell%7D%20-%20%5Cfrac%7B0.0592%20V%7D%7Bn%7D%20log%20%5Cfrac%7B%5BAgCl%5D%7D%7B%5BAg%5E%7B%2B%7D%5D%5BCl%5E%7B-%7D%5D%7D)
At equilibrium, 
= 0.00 V
Putting the given values into the above formula as follows.
![0.00 = E^{o}_{cell} - \frac{0.0592 V}{1} log \frac{1}{[Ag^{+}][Cl^{-}]}](https://tex.z-dn.net/?f=0.00%20%3D%20E%5E%7Bo%7D_%7Bcell%7D%20-%20%5Cfrac%7B0.0592%20V%7D%7B1%7D%20log%20%5Cfrac%7B1%7D%7B%5BAg%5E%7B%2B%7D%5D%5BCl%5E%7B-%7D%5D%7D)
= 
= 0.577 V
Hence, we will calculate the standard cell potential as follows.
= 0.222 V
Thus, we can conclude that value of for the half-cell reaction is 0.222 V.
Carbon has four valence electrons. These electrons are associated for a specific atom and is responsible for forming a bond to different atoms. For carbon, in order to agree with the octet rule, it should have 4 more electrons. For an oxygen atom, there are 6 valence electrons present so it would need two more electrons. Thus, carbon atoms would share electrons with another two oxygen atoms wherein each oxygen atom would form double bonds with the carbon atom. So, the characteristics of these bonds would be that all of the four valence electrons of the carbon are being shared.
A because of the temperature keeps gases like carbon dioxide dissolved
<span>A sample of C3H8 has 3.20 × 10^24 H atoms.
We will use Avogadro's number for this problem. Avogadro's number states that there are 6.022x 10^23 atoms per mole of a substance. We will use dimensional analysis, notice how the units cancel in the computation below:
</span>3.20 × 10^24 atoms H * (1 mole H/6.022x 10^23 atoms H) * (3 moles C/8 moles H) * (6.022x 10^23 atoms C/1 mole C) = 1.2 x 10^24 atoms C
To get the total mass of the sample in grams, let us note that there are 3 moles of carbon and 8 moles of hydrogen per mole of C3H8, and using the molecular weights of C (12 g/mol) and H (1 g/mol), we get (12*3)+(1*8)= 44 g/mol as the molar mass.
3.20 × 10^24 atoms H * (1 mole H/6.022x 10^23 atoms H) * (1 mole C3H8/8 moles H) * (44 g C3H8 / 1 mole C3H8) = 29.23 g C3H8<span>
</span>
