When conducting a search to identify a text's credibility and reliability, you have to check the following characteristics:
- Sources: where the information is obtained and it is supposed to be true. It is said that you need at least three different sources that explain the same information for it to be validated.
- Is the article is current?: articles could change all the time, specially scientific ones because new discoveries can change what was discovered before, so it is important to check if the text you are reading is current or not, and if it is not, you need to check if something has changed during all those years.
<h3>Article's credibility</h3>
In this exercise, you have to present an article and describe the purpose of the source and if the article is current or not.
For example, let's select an article called "How using social media affects teenagers".
The purpose of the sources in this article is to demonstrate how social media affects teenagers using different surveys.
Check more information about sources here brainly.com/question/24708478
Answer:
The parents and offspring all have phenotype ww. That leaves 100% probability of short wings and 0% long wings.
Explanation:
If long wings are a dominant trait, that means short wings are recessive. If two short winged flies are crossed, each of their phenotypes are ww. Therefore, each of their offspring also have phenotype ww, or short wings.
First of all, that's not an equation. An equation needs an 'equals' sign ( = ),
so you need something like
Amount present = a e^-0.0025t .
'a' = amount present when t = 0 .
The half-life is the time it takes for the original amount to decay to half of it.
That's just 't' when e^-0.0025t = 1/2
Take the natural log of each side: -0.0025t = ln(0.5)
Divide each side by -0.0025 : t = ln(0.5) / (-0.0025) =
(-0.69315) / (-0.0025) =
<em>t = 277.26 minutes</em>
( 4hrs 37min 15.5sec)
Rounded to nearest tenth: t = 277.3 minutes .
Answer:
Incomplete question. Complete question is: An electric drill starts from rest and rotates with a constant angular acceleration. After the drill has rotated through a certain angle, the magnitude of the centripetal acceleration of a point on the drill is twice the magnitude of the tangential acceleration. Determine the angle through which the drill rotates by this point.
The answer is : Δ θ = 1 rad
Explanation:
Ok, so the condition involves the centripetal acceleration and the tangential acceleration, so let’s start by writing expressions for each:
Ac= centripetal acceleration At= tangential acceleration
Ac = V² / r At = r α
Because we have to determine the angle ultimately, therefore we should convert the linear velocity into angular velocity in the expression for centripetal acceleration
V = r ω
Ac = (r ω)² / r = r² ω² / r
Ac = r ω²
now that we have expressions for the centripetal and tangential acceleration, we can write an equation that expresses the condition given: The magnitude of the centripetal acceleration is twice the magnitude of the tangential acceleration.
Ac = 2 At
That is,
r ω² = 2 r α
it is equivalent to;
ω² = 2 α
now we have the relation between angular speed and angular acceleration, but we also need to determine the angular displacement as well. Therefore choose a kinematics equation that doesn’t involve time because time is not mentioned in the question. Thus,
ω² – ω°² = 2 α Δ θ
such that ω° = 0
and ω² = 2 α
therefore;
2 α - 0 = 2 α Δ θ
2 α = 2 α Δ θ
So the angle will be : Δ θ = 1 rad
Answer:
The velocity will be v = 165.83[m/s]
Explanation:
This is a problem where the definition of kinetic energy can be applied, which can be determined with the following equation.
![E_{k}=\frac{1}{2}*m*v^{2}\\ where:\\m = mass = 80000[kg]\\v = velocity [m/s]\\E_{k}= kinetic energy [J]=1100000000[J]\\Replacing:\\v=\sqrt{\frac{2*E_{k} }{m} } \\v=\sqrt{\frac{2*1100000000 }{80000} }\\v=165.83[m/s]](https://tex.z-dn.net/?f=E_%7Bk%7D%3D%5Cfrac%7B1%7D%7B2%7D%2Am%2Av%5E%7B2%7D%5C%5C%20%20%20where%3A%5C%5Cm%20%3D%20mass%20%3D%2080000%5Bkg%5D%5C%5Cv%20%3D%20velocity%20%5Bm%2Fs%5D%5C%5CE_%7Bk%7D%3D%20kinetic%20energy%20%5BJ%5D%3D1100000000%5BJ%5D%5C%5CReplacing%3A%5C%5Cv%3D%5Csqrt%7B%5Cfrac%7B2%2AE_%7Bk%7D%20%7D%7Bm%7D%20%7D%20%5C%5Cv%3D%5Csqrt%7B%5Cfrac%7B2%2A1100000000%20%7D%7B80000%7D%20%7D%5C%5Cv%3D165.83%5Bm%2Fs%5D)
