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3 years ago

if the amplitude of sine curve is 4 and the frequency is 1 with no phase shift, what is the function that descirbes this curve?

Physics

1 answer:

Vlada [557]3 years ago

8 0

Answer:

y = 4 Sin (2πt)

Explanation:

Amplitude, A = 4

frequency, f = 1

Wave function is given by

y = A sinωt

where, ω is angular frequency

ω = 2 π f = 2 π x 1 = 2π

So, the desired wave function

y = 4 Sin (2πt)

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Professional Application. A 96 kg football player catches a 0.900 kg ball with his feet off the ground with both of them moving

Zarrin [17]

To solve this problem it is necessary to apply the equations related to the conservation of momentum.

This definition can be expressed as

$m_1u_1+m_2u_2 = (m_1+m_2)V_f$

Where

$m_{1,2}$ = Mass of each object

$u_{1,2}$ = Initial Velocity of each object

$V_f$ = Final velocity

Rearranging the equation to find the final velocity we have,

$V_f = \frac{m_1u_1+m_2u_2}{(m_1+m_2)}$

Our values are given as

$m_1 = 96Kg\\m_2 = 0.9Kg\\u_1 = 6.3m/s\\u_2 = 27.4m/s$

Replacing we have,

$V_f = \frac{(96)(6.3)+(0.9)(27.4)}{(96+0.9)}$

$V_f = 6.4959m/s$

Therefore the final velocity is 6.5m/s

3 0

3 years ago

irius, the brightest star in the sky, is 2.6 parsecs (8.6 light-years) from Earth, giving it a parallax of 0.379 arcseconds. Ano

Norma-Jean [14]

The actual distance of Regulus from Earth is 23.81 parsecs.

Given:

Parallax of Regulus, p = 0.042 arc seconds

Calculation:

When an observer changes their position, an apparent change in the object's position takes place. This change can be calculated using the angle ( or semi-angle) made by the observer and object i.e. the angle made between the two lines of observation from the object to the observer.

Thus from the relation of parallax of a celestial body we get:

S = 1/ tan p ≈ 1 / p

where S is the actual distance between the object and the observer

p is the parallax angle observed

Here for Regulus, we get:

S = 1 / p

= 1 / (0.042) [ 1 parsecs = 1 arcseconds ]

= 23.81 parsecs

We know that,

1 parsecs = 3.26 light-years = 206,000 AU

Converting the actual distance into light years we get:

23.81 parsecs = 23.81 × (3.26 light yrs) = 77.658 light-years

Therefore, the actual distance of Regulus from Earth is 23.81 parsecs which is 77.658 in light years.

Learn more about astronomical units here:

<u>brainly.com/question/16471213</u>

#SPJ4

6 0

1 year ago

Key difference of the celsius scale and kevin scale

mixer [17]

Their 'degrees' are the same size. The difference between the Celsius
and Kelvin scales is their zero-point. Zero Kelvin is the absolute zero of
nature and Physics. Zero Celsius is the melting/freezing point of water,
273.15 higher than absolute zero.

6 0

3 years ago

Vector A⃗ points in the negative y direction and has a magnitude of 5 km. Vector B⃗ has a magnitude of 15 km and points in the p

Alexxandr [17]

Answer:

magnitude of A − B = 15.81 km

Explanation:

Vector A points in the negative y-direction and has a magnitude of 5 km. Vector B points in the positive x-direction and has a magnitude of 15 km.

According to Cartesian coordinate system, the resultant will start either from tail of A and ends at head of B and vice-versa.

A(0,-5)

B(15,0)

A - B = (-15 i - 5 j )

Magnitude of the vector is given by

|A - B| = $\sqrt{(-15)^{2}+(-5)^{2}}$

|A - B| = $\sqrt{250}$

|A - B| = 15.81 km

7 0

3 years ago

Scientist who first proposed the theory that the continents drifted is __________

Aloiza [94]

Answer:

Alfred Wegener

Explanation:

Alfred Wegener is a german meteorologist who proposed the theory that the continents drifted, and he presented it to the German Geological Society on January 1912.

4 0

3 years ago