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Andru [333]
3 years ago
7

PLEASE HELP ME WITH THIS ONE QUESTION

Physics
1 answer:
STALIN [3.7K]3 years ago
7 0

Answer:

282,250 joules

Explanation:

Given that :

Mass of liquid water = 125 gram.

Latent heat of vaporization, L = 2258 J/g

Recall :

Q = mL

Where, Q = quantity of heat required in Joules

Mass) m

L = latent heat of vaporization

Q = mL

Q = 125 g * 2258j/g

Q = 282,250 joules

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one of the four wave interactions is very important to how plants use light to grow. guess which interaction this is
KiRa [710]
The photosynthetic wave interaction between visible light and a photosensitive part of a plant is very important t how plants use light to grow. 
The frequency range and intensity levels of this light, I don't know. 

Maybe the above ???
6 0
3 years ago
Determine whether each of the statements below is true or false, and place it in the appropriate bin. Objects with equal speeds
lisov135 [29]

Objects with equal speeds definitely have equal velocities. -- FALSE.  For equal velocities, they also have to be going in the same direction.

If you are given an object's velocity, you can definitely determine its speed. -- TRUE.  If you know the velocity, then you know both the object's speed and its direction.

If you know the distance an object travels, and the time it takes to do so, you can determine the object's velocity. -- FALSE. Knowing the distance and time, you can figure out the object's speed.  But if you don't also know the direction it's moving, then you can't say what its velocity is.

If an object moves at constant speed, it must also be moving at constant velocity. -- FALSE.  Besides constant speed, it also needs to move in a straight line to have constant velocity.  If it turns, its velocity changes, even if its speed doesn't.

If an object moves at constant velocity, it must also be moving at constant speed. -- TRUE.  Constant velocity means its speed AND its direction are not changing.

Objects with equal velocities definitely have equal speeds. -- TRUE.  If their velocities are equal, then their speeds are equal AND they're moving in the same direction.

After laboring through this one, I'm wondering if there can possibly be any more ways to say the same thing.

7 0
3 years ago
A strand of 10 lights is plugged into a outlet. How can you determine if the lights are connected in series or parrel
NeTakaya

Answer:

C) Unscrew one light. If the other lights turn off, it's a series circuit.

Explanation:

THIS IS THE COMPLETE QUESTION BELOW;

A strand of 10 lights is plugged into an outlet. How can you determine if the lights are connected in series or parallel? A) Unscrew one light. If the other lights stay on, it's a series circuit. B) Unplug the strand. If the first light stays on, it's a series circuit. C) Unscrew one light. If the other lights turn off, it's a series circuit. D) Cut the strand in half. If the plugged in half stays on, it's a series circuit.

SERIES CIRCUIT

In this circuit, the components there are in the same path, the entire circuit has the same current, each of the components posses different voltage drop. Hence, failure of one components to work, there will be break in entire circuit then other components cease to work.

PARALLEL CIRCUIT

This circuit has equal voltage drop across all the components, any problem in a component will not has effect on other components.

Therefore, if one want to determine if a light connection is in series or in parallel, one of the light can be unplugged if others stop working it means it's series, if other works it's parallel.

5 0
3 years ago
Why does a balloon stick to a sweater after it has been rubbed against it?
Nataly [62]
Hello,

The balloon sticks to a sweater after it has been rubbed against it because once you rub a balloon against the sweater, the balloon steals electrons from the sweater, which leaves the sweater positively charged and the balloon negatively charged.

Mark brainliest if helped!

8 0
3 years ago
Read 2 more answers
Show that the electric potential along the axis of a uniformly charged disk of radius R and charge density sigma is given by by
OlgaM077 [116]

Explanation:

Area of ring \ 2{\pi} a d a

Charge of on ring d q=-(\ 2{\pi} a d a)

Charge on disk

Q=-\left(\pi R^{2}\right)

\begin{aligned}d v &=\frac{k d q}{\sqrt{x^{2}+a^{2}}} \\&=2 \pi-k \frac{a d a}{\sqrt{x^{2}+a^{2}}} \\v(1) &=2 \pi c k \int_{0}^{R} \frac{a d a}{\sqrt{x^{2}+a^{2}}} \cdot_{2 \varepsilon_{0}}^{2} R \\&=2 \pi \sigma k[\sqrt{x^{2}+a^{2}}]_{0}^{2} \\&=\frac{2 \pi \sigma}{4 \pi \varepsilon_{0}}[\sqrt{z^{2}+R^{2}}-(21)] \\&=\frac{\sigma}{2}(\sqrt{2^{2}+R^{2}}-2)\end{aligned}

Note: Refer the image attached

8 0
4 years ago
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