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Andrews [41]
3 years ago
9

Look at the reaction below. Upper H subscript 2 upper S upper O subscript 4 (a q) plus upper C a (upper O upper H) subscript 2 (

a q) right arrow upper C a upper S upper O subscript 4 (a q) plus 2 upper H subscript 2 upper O (l). Which substance is the base in the reaction? A. 2H2O (l) B. H2SO4 (aq) C. CaSO4 (aq) D. Ca(OH)2 (aq)

Chemistry
2 answers:
Mkey [24]3 years ago
6 0

Answer:

Its D  

Explanation:

Did it on edge

Cloud [144]3 years ago
3 0

Answer:

3 and

Explanation:

Why did you type the whole question we can see it

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The protein lysozyme unfolds at a transition temperature of 75.5°C, and the standard enthalpy of transition is 509 kJ mol-1. Cal
spin [16.1K]

Answer:

0.4774 KJ/K.mol

Explanation:

We are told that the transition at 25.0°C occurs in three steps. Steps i, ii and iii.

Thus;

the entropy of unfolding of lysozyme = ΔS_i + ΔS_ii + ΔS_iii

Now,

C_p,m(unfolded protein) = C_p,m(folded protein) + 6.28 kJ/K.mol

Now, for the first process, ΔS_i is given as;

ΔS_i = C_p,m × In(T2/T1)

We are given;

T1 = 25°C = 25 + 273.15K = 298.15 K

T2 = 75.5°C = 75.5 + 273.15 K=348.65 K

Thus;

ΔS_i = C_p,m × In(348.65/298.15)

Now, for the third process, ΔS_iii is given as;

ΔS_iii = (C_p,m + 6.28 kJ/K.mol) × In(T1/T2)

Thus;

ΔS_iii = (C_p,m + 6.28 kJ/K.mol) × In(298.15/348.65)

Now, we don't know C_pm. So, we have to find a way to eliminate it. We will do it by rewriting In(298.15/348.65) in such a way that when ΔS_iii is added to ΔS_i, C_p,m will cancel out. Thus;

In(298.15/348.65) can also be written as;

In(348.65/298.15)^(-1) or

- In(348.65/298.15)

Thus;

ΔS_iii = - [(C_p,m + 6.28 kJ/K.mol) × In(298.15/348.65)]

Now, let's add ΔS_iii to ΔS_i to get;

ΔS_i + ΔS_iii = [C_p,m × In(348.65/298.15)] + [(-C_p,m - 6.28 kJ/K.mol) × In(348.65/298.15)]

ΔS_i + ΔS_iii = [C_p,m × In(348.65/298.15)] - [C_p,m × In(348.65/298.15)] - [6.28In(348.65/298.15)]

First 2 terms will cancel out to give;

ΔS_i + ΔS_iii = -6.28In(348.65/298.15)

ΔS_i + ΔS_iii = -0.9826 KJ/K.mol

Now,for process ii;

ΔS_ii = standard enthalpy of transition/Transition Temperature

Thus;

ΔS_ii = (509 KJ/K.mol)/348.65

ΔS_ii = 1.46 KJ/K.mol

Thus;

the entropy of unfolding of lysozyme = ΔS_i + ΔS_ii + ΔS_iii = -0.9826 + 1.46 = 0.4774 KJ/K.mol

5 0
3 years ago
A student decided to research primate psychology for their science project. They measured how long it took gorillas to adapt to
Gwar [14]

Answer: the answer is  D im pretty sure

Explanation:

3 0
3 years ago
You have three elements, A, B, and C, with the following electronegativity values:
DerKrebs [107]

#AB

Electronegativity difference=3.3-2.9=0.4.

  • It's a covalent bond.
  • Gaseous or solid substance.

#AC

Electronegativity difference=3.3-0.7=2.6

  • Its an ionic bond.
  • Solid substance.

#BC

Electronegativity difference=2.9-0.7=2.3

  • It's an ionic bond
  • Solid substance

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2 years ago
Why is it difficult for countries to reduce emissions of carbon dioxide
Natalka [10]

Answer:

Curbing global carbon dioxide emissions has been a challenge, primarily because they are being driven higher by countries with low per capita emissions.

Explanation:

"just trust me bro"

3 0
3 years ago
**ASAP**
jek_recluse [69]

the answer is C) . I hope this was helpful!

4 0
3 years ago
Read 2 more answers
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