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ololo11 [35]
2 years ago
7

An ignition coil is an example of a. A. Step-up transformer. B. Step- down transformer. C. Relay.

Engineering
1 answer:
podryga [215]2 years ago
3 0

Answer:

D

Explanation:

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At an auction of antiques, a bidder for a particular porcelain statue would be trying to ________(a) Maximize the difference bet
alex41 [277]

Answer: MINIMIZE INPUT

Explanation: AUCTION this is a process of selling a product,an Art work other tradeable assets like stocks, bonds based on the person with the highest BIDDING( Higher amount). In most cases the person buying will try to control his bidding to the MINIMUM AMOUNT in order for him to avoid spending higher than expected. Auction sale is sometimes used when trying to sell off old products which has been held for a long time, sometimes Auctions are used to raise funds for a particular Reason like the sale of ARTIFACTS.

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A lake has a carrying capacity of 10,000 fish. At the current level of fishing, 2,000 fish per year are taken with the catch uni
arlik [135]

Answer:

The population size would be p' = 5000

The yield would be    MaxYield = 2082 \ fishes \ per \ year

Explanation:

So in this problem we are going to be examining the application of a  population dynamics a fishing pond and stock fishing and objective would be to obtain the maximum sustainable yield and and the population of the fish at the obtained maximum sustainable yield,  so basically we would be applying an engineering solution to fishing

 

    So the current  yield which is mathematically represented as

                               \frac{dN}{dt} =   \frac{2000}{1 \ year }

 Where dN is the change in the number of fish

            and dt is the change in time

So in order to obtain the solution we need to obtain the  rate of growth

    For this we would be making use of the growth rate equation which is

                                      r = \frac{[\frac{dN}{dt}] }{N[1-\frac{N}{K} ]}

  Where N is the population of the fish which is given as 4,000 fishes

          and  K is the carrying capacity which is given as 10,000 fishes

             r is the growth rate

        Substituting these values into the equation

                              r = \frac{[\frac{2000}{year}] }{4000[1-\frac{4000}{10,000} ]}  =0.833

The maximum sustainable yield would be dependent on the growth rate an the carrying capacity and this mathematically represented as

                      Max Yield  = \frac{rK}{4} = \frac{(10,000)(0.833)}{4} = 2082 \ fishes \ per \ year

So since the maximum sustainable yield is 2082 then the the population need to be higher than 4,000 so in order to ensure a that this maximum yield the population size denoted by p' would be

                          p' = \frac{K}{2}  = \frac{10,000}{2}  = 5000\ fishes          

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Develop a chase plan that matches the forecast and compute the total cost of your plan. (Negative amounts should be indicated by
vladimir2022 [97]

Answer:

The answer for the question :

"Develop a chase plan that matches the forecast and compute the total cost of your plan. (Negative amounts should be indicated by a minus sign. Leave no cells blank - be certain to enter "0" wherever required. Omit the "$" sign in your response.)"

is explained in the attachment.

Explanation:

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