Answer:
204g of NH3
Explanation:
The balanced equation for the reaction is given below:
N2 + 3H2 —> 2NH3
Next, we shall determine the number of mole NH3 produced by reacting 6moles of N2. This is illustrated below:
From the balanced equation above,
1 mole of N2 reacted to produce 2 moles of NH3.
Therefore, 6 moles of N2 will react to produce = 6 x 2 = 12 moles of NH3.
Finally, we shall convert 12 moles of NH3 to grams. This is illustrated below:
Number of mole of NH3 = 12 moles.
Molar mass of NH3 = 14 + (3x1) = 17g/mol
Mass of NH3 =..?
Mass = mole x molar mass
Mass of NH3 = 12 x 17
Mass of NH3 = 204g.
Therefore, 204g of NH3 will be produced from the reaction.
Answer:
Approx. 4⋅g.
Explanation:
Moles of sulfuric acid =10.0⋅g98.08⋅g⋅mol−1=0.102⋅mol.
Now we have the molar quantity of sulfuric acid that react; we also have the stoichiometric equation that shows the molar equivalence of sulfuric acid, and lithium hydroxide.
Given the stoichiometry,
mass of water =0.102⋅mol×2×18.01.g.mol−1=??⋅g.
Why did I multiply the mass in this equation by 2? Am I pulling your leg?
Answer:
Explanation:
The formula for sodium is Na. It does not form a molecule in some way.
1 mol Na = 6.02*10^23 atoms
3.91 mol = x Cross multiply
x = 3.91 * 6.02 * 10^23
x = 23.65 * 10^23
x = 2.365 * 10^24
Scientific notation is always expressed as a number 1 ≤ x < 10
Which lists the correct order of the steps?<br> 4,2,1,3<br>4,1,3,2<br> 4,3,1, 2<br>4, 2, 3.1
Alik [6]
Answer:
4,3,1,2 thise is my answer.
