Answer:
time required after impact for a puck is 2.18 seconds
Explanation:
given data
mass = 30 g = 0.03 kg
diameter = 100 mm = 0.1 m
thick = 0.1 mm = 1 ×
m
dynamic viscosity = 1.75 ×
Ns/m²
air temperature = 15°C
to find out
time required after impact for a puck to lose 10%
solution
we know velocity varies here 0 to v
we consider here initial velocity = v
so final velocity = 0.9v
so change in velocity is du = v
and clearance dy = h
and shear stress acting on surface is here express as
= µ 
so
= µ 
............1
put here value
= 1.75× × 
= 0.175 v
and
area between air and puck is given by
Area = 
area = 
area = 7.85 × 
m²
so
force on puck is express as
Force = × area
force = 0.175 v × 7.85 × 
force = 1.374 × v
and now apply newton second law
force = mass × acceleration
- force = 
- 1.374 × v = 
t = 
time = 2.18
so time required after impact for a puck is 2.18 seconds
I would feel warm because putting cold and hot together is gonna be warm because with the cold it is cooling down the hot to make warm
Answer:
11.95m/s
Explanation:
A moving object has a kinetic energy of 150 J and a momentum of 25.1 kg·m/s.
a) Find the speed of the object. Answer in units of m
K. E =½mv²
150= ½mv²
Multiply both sides by 2
mv² = 300
Divide both sides by v²
m = 300/v² .................. Equation 1
Momentum is the product of mass and velocity
Momentum = mv
25.1 = mv
Divide both sides by v
m = 25.1/v ................ Equation 2
Equate equations 1 and 2
300/v² = 25.1/v
Cross multiply
25.1v² = 300v
Multiply v with both sides
25.1v = 300
Divide both sides by 25.1
v = 300/25.1
V = 11.95m/s
I hope this was helpful, please mark as brainliest
Answer:
Period for 1 revolution is 1.75 seconds
Explanation:
given data
revolutions R = 8
time t = 14 seconds
to find out
What is the period
solution
we know that Period is the time per revolution
so here period formula that is express as
period = 
= 
= 0.57 revolution in one second
so in 1 revolution = 
seconds
so in 1 revolution = 1.75 seconds
so period for 1 revolution is 1.75 seconds
Answer:
Speed of block after the bullet emerges = 1.5 m/s
Explanation:
Here momentum is conserved.
Initial momentum = Final momentum.
Mass of bullet = 10 g = 0.01 kg
Initial Velocity of bullet = 300 m/s
Mass of block = 1 kg
Initial Velocity of block = 0 m/s
Final Velocity of bullet = 50% of initial velocity. = 150 m/s
We need to find final velocity of block. Let it be v
We have
Initial momentum = 0.01 x 300 + 1 x 0 = 3 kg m/s
Final momentum = 0.01 x 150 + 1 x v = 1.5 + v
Equating
3 = 1.5 + v
v = 1.5 m/s
Speed of block after the bullet emerges = 1.5 m/s
