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3 years ago

5

a car of mass 1,000 kilograms is moving initially at the speed of 22 meters/second. when the brakes are applied, it takes the ca

r 3.0 seconds to stop. what is the force required to stop the car?

1 answer:

Evgen [1.6K]3 years ago

5 0

It i believe it would be 7.3 × 10∧3.

correct me if im wrong

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A mouse jumps horizontally from a box of height 0.25m. If the mouse jumps with a speed of 2.1 m/s, how far from the box does th

Sladkaya [172]

The mouse would land 0.47 m away from the box.

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3 years ago

Read 2 more answers

What is the energy stored between 2 Carbon nuclei that are 1.00 nm apart from each other? HINT: Carbon nuclei have 6 protons and

Andrei [34K]

Answer:

$A. 8.29\times 10^{-18}\ J$

Explanation:

Given that:

p = magnitude of charge on a proton = $1.6\times 10^{-19}\ C$

k = Boltzmann constant = $9\times 10^{9}\ Nm^2/C^2$

r = distance between the two carbon nuclei = 1.00 nm = $1.00\times 10^{-9}\ m$

Since a carbon nucleus contains 6 protons.

So, charge on a carbon nucleus is $q = 6p=6\times 1.6\times 10^{-19}\ C=9.6\times 10^{-19}\ C$

We know that the electric potential energy between two charges q and Q separated by a distance r is given by:

$U = \dfrac{kQq}{r}$

So, the potential energy between the two nuclei of carbon is as below:

$U= \dfrac{kqq}{r}\\\Rightarrow U = \dfrac{kq^2}{r}\\\Rightarrow U = \dfrac{9\times10^9\times (9.6\times 10^{-19})^2}{1.0\times 10^{-9}}\\\Rightarrow U =8.29\times 10^{-18}\ J$

Hence, the energy stored between two nuclei of carbon is $8.29\times 10^{-18}\ J$ .

8 0

3 years ago

P= F/A make a the subject

lawyer [7]

Answer:

a=f/p

Explanation:

p=f/a

f=p×a

this all

4 0

3 years ago

In the two-slit experiment, monochromatic light of wavelength 600 nm passes through a 19) pair of slits separated by 2.20 x 10-5

kumpel [21]

Explanation:

It is given that,

Wavelength of monochromatic light, $\lambda=600\ nm=6\times 10^{-7}\ m$

Slits separation, $d=2.2\times 10^{-5}\ m$

(a) We need to find the angle corresponding to the first bright fringe. For bright fringe the equation is given as :

$d\ sin\theta=n\lambda$ , n = 1

$\theta=sin^{-1}(\dfrac{\lambda}{d})$

$\theta=sin^{-1}(\dfrac{6\times 10^{-7}}{2.2\times 10^{-5}})$

$\theta=1.56^{\circ}$

(b) We need to find the angle corresponding to the second dark fringe, n = 1

So, $d\ sin\theta=(n+\dfrac{1}{2})\lambda$

$sin\theta=\dfrac{3\lambda}{2d}$

$\theta=sin^{-1}(\dfrac{3\lambda}{2d})$

$\theta=sin^{-1}(\dfrac{3\times 6\times 10^{-7}}{2\times 2.2\times 10^{-5}})$

$\theta=2.34^{\circ}$

Hence, this is the required solution.

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3 years ago

In the first seconds of flight, the Saturn V rocket achieved an altitude of m, and a velocity of m/s. The rocket weighed approxi

jolli1 [7]

The average power produced by the rocket is the product of force exerted by the rocket and the velocity of the rocket.

<h3>Average power produced by the rocket</h3>

The average power produced by the rocket is calculated as follows;

P = FV

where;

P is the average power
F is the force exerted by the rocket
V is the velocity of the rocket

Thus, the average power produced by the rocket is the product of force exerted by the rocket and the velocity of the rocket.

Learn more about average power here: brainly.com/question/19415290

#SPJ1

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1 year ago