Answer:
Web application Firewall (WAF)
Explanation:
The Web application Firewall (WAF) will be recommended. This will enormously help any organisation that is having a struggle of differentiating threats from normal traffic and access to systems.
WAF is also going to It aggregate data and provide metrics that will assist in identifying malicious actors. Another vital function of WAF will be to block unwanted web traffic from accessing your site. It will protect against hacks, brute force attacks, DDoS attacks, cross-site scripting, SQL injection, and zero-day exploits.
Answer:
insert the disk in the laptop, wait of a minute or 2 and then a folder will open in my PC.
Answer:
h_f = 15 ft, so option A is correct
Explanation:
The formula for head loss is given by;
h_f = [10.44•L•Q^(1.85)]/(C^(1.85))•D^(4.8655))
Where;
h_f is head loss due to friction in ft
L is length of pipe in ft
Q is flow rate of water in gpm
C is hazen Williams constant
D is diameter of pipe in inches
We are given;
L = 1,800 ft
Q = 600 gpm
C = 120
D = 8 inches
So, plugging in these values into the equation, we have;
h_f = [10.44*1800*600^(1.85)]/(120^(1.85))*8^(4.8655))
h_f = 14.896 ft.
So, h_f is approximately 15 ft
Answer:
a)A constant volume process is called isochoric process.
b)Yes
c)Work =0
Explanation:
Isochoric process:
A constant volume process is called isochoric process.
In constant volume process work done on the system or work done by the system will remain zero .Because we know that work done give as
work = PΔV
Where P is pressure and ΔV is the change in volume.
For constant volume process ΔV = 0⇒ Work =0
Yes heat transfer can be take place in isochoric process.Because we know that temperature difference leads to transfer of heat.
Given that
Initial P=10 MPa
Final pressure =15 MPa
Volume = 100 L
Here volume of gas is constant so the work work done will be zero.
Answer:32.4m/
Explanation:
Given data
=0.4m
Intial angular velocity
=4rad/s
angular acceleration
=5rad/
angular velocity after 1 sec
=
+
=4+5
=9rad/s
Velocity of point on the outer surface of disc
=
v=
m/s=3.6m/s
Normal component of acceleration
=
=
=32.4m/
