Ask question

Ask question

All categories

3 years ago

11

Which of these rocks is most likely to be damaged by acid rain?

2 answers:

natima [27]3 years ago

7 0

the answer is limestone because it is the weakest

bonufazy [111]3 years ago

3 0

The limestone is the answer

You might be interested in

A gas has a pressure of 8.5atm and occupies 24L at 25∘C. What volume (in liters) will the gas occupy if the pressure is increase

Vesna [10]

The volume (in liters) that the gas will occupy if the pressure is increased to 13.5 atm and the temperature is decreased to 15 °C is 15 L

From the question given above, the following data were obtained:

Initial pressure (P₁) = 8.5 atm

Initial volume (V₁) = 24 L

Initial temperature (T₁) = 25 °C = 25 + 273 = 298 K

Final pressure (P₂) = 13.5 atm

Final temperature (T₂) = 15 °C = 15 + 273 = 288 K

<h3>Final volume (V₂) =? </h3>

The final volume of the gas can be obtained by using the combined gas equation as illustrated below:

$\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\\\frac{8.5 * 24}{298} = \frac{13.5 * V_{2}}{288}\\\\ \frac{204}{298} = \frac{13.5 * V_{2}}{288}\\\\$

Cross multiply

298 × 13.5 × V₂ = 204 × 288

4023 × V₂ = 58752

Divide both side by 4023

$V_{2} = \frac{58752}{4023}\\\\$

<h3>V₂ = 15 L </h3>

Therefore, the final volume of the gas is 15 L

Learn more: brainly.com/question/25547148

3 0

2 years ago

Calculate the equilibrium constant for the decomposition of water 2h2o(l)  2h2(g) + o2(g) at 25°c, given that g°f (h2o(l)) = –

kow [346]

Answer:

2.6 ×10^-42

Explanation:

From

∆G= -RTlnK

∆G= -237.2 KJmol-1 or -237.2×10^3 Jmol-1

R= 8.314 Jmol-1K-1

T= 25°C + 273= 298K

-237.2×10^3= 8.314 × 298 × ln K

ln K= -237.2×10^3/2477.572

K = 2.6 ×10^-42

3 0

3 years ago

2. Use the Henderson-Hasselbalch equation to estimate the pH of a buffer solution that is composed of 20 mL of 10 M sodium forma

Mkey [24]

Answer:

pH of buffer =4.75

Explanation:

The pH of buffer solution is calculated using Henderson Hassalbalch's equation:

$pH=pKa+log[\frac{[salt]}{[acid]}$

Given:

pKa = 3.75

concentration of acid = concentration of formic acid = 1 M

concentration of salt = concentration of sodium formate = 10 M

$pH=3.75+log[\frac{10}{1}]=3.75+1=4.75$

pH of buffer =4.75

7 0

3 years ago

Agitation prevents settling in a?

VashaNatasha [74]

D gaseous mixture I hope it helps

5 0

2 years ago

professor190 [17]

Hi so from what I can see the pizza as a distant or and you just have to convert the grams of glucose into moles. Most teachers ask for this format

7 0

2 years ago