Enem 2003 embalagens longa vida brick

The vector quantity that defines the distance and direction between two positions. It is a change in your position.

pantera1 [17]

Answer:

Displacement

Explanation:

To describe the change in position you need to indicate the distance between the final and initial positions and the direction in which you moved. The distance is the magnitude.

The quantities that need both magnitude and direction to be described are named vector quantities or, just, vectors.

The vector quantity that defines both the distance and direction between two positions describes the change in your position and is named displacement. For instance, to indicate how you can goe to the supermarket from your house you cannot just say walk 2 miles. You need to indicate the direction; let's say 2 miles North. In this case, the displacement when you goe from your house to the supermarket is 2 miles North. And it is different of the displacement when you comeback from the supermarket to your house, because it would be 2 miles South.

5 0

3 years ago

PLEASE HELP ME,, I WOULD BE SO HAPPY

Scrat [10]

Answer:

thanks for the points liar

Explanation:

4 0

3 years ago

A Neglecting air resistance, a ball projected straight upward so it remains in the air for 10 seconds needs an initial speed of

ololo11 [35]

Answer:

The initial velocity is 50 m/s.

(C) is correct option.

Explanation:

Given that,

Time = 10 sec

For first half,

We need to calculate the height

Using equation of motion

$v^2=u^2+2gh$

$h =\dfrac{v^2}{2g}$ ....(I)

For second half,

We need to calculate the time

Using equation of motion

$h =ut+\dfrac{1}{2}gt_{2}^2$

$h=0+\dfrac{1}{2}gt_{2}^2$

$t_{2}=\sqrt{\dfrac{2h}{g}}$

Put the value of h from equation (I)

$t_{2}=\sqrt{\dfrac{2\times v^2}{g^2}}$

$t_{2}=\dfrac{v}{g}$

According to question,

$t_{1}+t_{2}=10$

$t_{1}=t_{2}$

Put the value of t₁ and t₂

$\dfrac{v}{g}+\dfrac{v}{g}=10$

$\dfrac{2v}{g}=10$

$v=\dfrac{10\times g}{2}$

Here, g = 10

The initial velocity is

$v=\dfrac{10\times10}{2}$

$v=50\ m/s$

Hence, The initial velocity is 50 m/s.

3 0

2 years ago

On a roller coaster ride the total mass of a cart - with two passengers included - is 319 kg. Peak K is at 43.6 m above the grou

Dafna1 [17]

The mechanical energy is lost due to friction between the two peak is 78,458.688 J

<h3>What is mechanical energy?</h3>

The mechanical energy is the sum of kinetic energy and the potential energy of an object at any instant of time.

M.E = KE +PE

Given is a roller coaster ride the total mass of a cart - with two passengers included - is 319 kg. Peak K is at 43.6 m above the ground and peak L is at 24.4 m. At location K the speed of the cart is 16.4 m/s, and at location L it is 12.4 m/s.

Total energy at peak K,

TE₁ = 1/2 mv₁² +mgh₁

Substitute the values, we get

TE₁ = 1/2 x319 x 16.4² +319 x 9.81 x 43.6

TE₁ = 179,340. 524 J

Total energy at peak L,

TE₂ = 1/2 mv₂² +mgh₂

Substitute the values, we get

TE₂ = 1/2 x319 x 12.4² +319 x 9.81 x 24.4

TE₂ = 100,881. 836 J

The mechanical energy lost is

M.E = TE₁ -TE₂

M.E = 179,340. 524 J - 100,881. 836 J

M.E = 78,458.688 J

Thus, the mechanical energy is lost due to friction between the two peak i

Learn more about mechanical energy.

brainly.com/question/13552918

#SPJ1

7 0

1 year ago

HEre now can somebody help!! Pic is what i need help with

AleksAgata [21]

Answer:

which of the cars are speeding up: c

which of the cars or slowing down: a

which of the cars are maintaning a constant speed: b

Explanation:

8 0

2 years ago

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Enem 2003 embalagens longa vida brick​

Enem 2003 embalagens longa vida brick