The distance covered in the last second of motion is 737.5 m
Explanation:
The motion of the car is a uniformly accelerated motion, so we can use the suvat equations.
First of all, we have to find the velocity of the car when the last second of motion starts, that is the velocity of the car after t = 29 s. We can use the equation:
v = u + at
where
u = 0 is the initial velocity
is the acceleration
Substituting t = 29 s,
Now we can find the distance covered in the last second of motion by using
where
u = 725 m/s is the velocity at the beginning of the last second
t = 1 s is the time interval considered
is the acceleration
Substituting,
Note that the acceleration of is not realistic for a car, but I still have used the data of the problem.
Learn more about acceleration:
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