Answer:
The speed of the stone just before it hits the ground is 18.54 m/s
Explanation:
Given that,
Initial speed of the stone, u = 8 m/s
The stone is thrown downward from a height of 14 m
We need to find the speed of the stone just before it hits the ground. It can be calculated using third equation of motion as :

v is the speed of the stone just before it hits the ground


v = 18.54 m/s
So, the speed of the stone just before it hits the ground is 18.54 m/s. Hence, this is the required solution.
Is there a certain context to this question so that I can answer it better?
Answer:
Output voltage is 1.507 mV
Solution:
As per the question:
Nominal resistance, R = 
Fixed resistance, R = 
Gauge Factor, G.F = 2.01
Supply Voltage, 
Strain, 
Now,
To calculate the output voltage,
:
WE know that strain is given by:

Thus

Now, substituting the suitable values in the above eqn:


Light year is the unit of distance. It is the distance that an object travels in one year with the speed of light.
In short, Your Answer would be "Distance"
Hope this helps!