I just divided 1180 by the numbers on the list until I got an answer that was another number on the list. Then i took the greater number, 59, and set 6r + 5 equal to that like so:
Mean=0.48 standard deviation=0.01 thus using the z-score: P(x>0.5) we shall have the following: z=(0.5-0.48)/0.01=2 thus P(x>0.5) =1-P(x<0.5) =1-P(z<2) =1-0.9772 =0.0228
