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aksik [14]
3 years ago
11

How would you define physics class in your own words ?

Physics
1 answer:
Andrei [34K]3 years ago
3 0

Answer:

honestly i dont like physics class but for you im gonna write somethin' good but for me tho its B O R I N G

Explanation:

<em>Physics is the branch of science that deals with the structure of matter and how the fundamental constituents of the universe interact. It studies objects ranging from the very small using quantum mechanics to the entire universe using general relativity.</em>

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Answer:

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Explanation:

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3 years ago
If the electron just misses the upper plate as it emerges from the field, find the magnitude of the electric field.
Damm [24]

Answer:

The magnitude of the electric field be 171.76 N/C so that the electron misses the plate.

Explanation:

As data is incomplete here, so by seeing the complete question from the search the data is

vx_0=1.1 x 10^6

ax=0 As acceleration is zero in the horizontal axis so

Equation of motion in horizontal direction is given as

s_x=v_x_0 t

t=\frac{s_x}{v_x}\\t=\frac{2 \times 10^{-2}}{1.1 \times 6}\\t=1.82 \times 10^{-8} s

Now for the vertical distance

vy_o=0

than the equation of motion becomes

s_y=v_y_0 t+\frac{1}{2} at^2\\s_y=\frac{1}{2} at^2\\0.5 \times 10^{-2}=\frac{1}{2} a(1.82 \times 10^{-8})^2\\a=3.02 \times 10^{13} m/s^2

Now using this acceleration the value of electric field is calculated as

E=\frac{F}{q}\\E=\frac{ma}{q}\\E=\frac{m_ea}{q_e}\\

Here a is calculated above, m is the mass of electron while q is the charge of electron, substituting values in the equation

E=\frac{9.1\times 10^{-31} \times 3.02 \times 10^{13} }{1.6 \times 10^{-19}}\\E=171.76 N/C

So the magnitude of the electric field be 171.76 N/C so that the electron misses the plate.

5 0
3 years ago
The diagram shows the apparent motion of the Sun across the sky. EAST WEST Sunrise Which action causes the Sun to appear to move
Andreas93 [3]
C. West to east is the correct answer
8 0
3 years ago
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D. The environment
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3 years ago
A person standing on the surface of the earth has a weight of 650 N. What is its weight at a distance of two earth radii from th
snow_lady [41]

Answer:

72.22 N

Explanation:

F = weight

m = mass of body

M = mass of earth

R = radius of earth

G = universal constant of gravitation

F_1= 650 N

F_1 = GMm/R^2

two earth radius above the surface of the earth:

F_2=  GMm/(3R)^2=  GMm/9R^2= F_1/9= 650/9

=72.22 N

4 0
3 years ago
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