Answer:
h = 20 m
Explanation:
height (h) = 10 m
potential energy (PE) = 50 J
kinetic energy (KE) = 50 J
what is the maximum height reached by the ball
- At 10 meters above the ground potential energy (PE) = 50 J
mgh = 50
recall that height (h) = 10
mg (10) = 50
mg = 5 .....equation 1
- The total energy of the system at 10 meters is given as PE + KE = 100 Joules. From the conservation of energy the total energy in the system still remains the same at the maximum height, this is because energy can neither be created nor destroyed but can be transformed from one form to another.
- At the maximum height the velocity (v) of the system is 0, which means all its kinetic energy (KE) is converted to potential energy. Therefore the system consist only of potential energy.
KE + PE = 100
+ mgh = 100 J
velocity (v) = 0 at maximum height therefore
0 + mgh = 100
mgh = 100
recall that mg = 5 from equation 1, therefore
5h = 100
h = 20 m
- Weight (W) = 110 N
- Acceleration due to gravity (g) = 9.8 m/s^2
- Let the mass of the object be m.
- By using the formula, W = mg, we get,
- 110 N = 9.8 m/s^2 × m
- or, m = 110 N ÷ 9.8 m/s^2
- or, m = 11.2 Kg
<u>Answer:</u>
<em><u>The </u></em><em><u>mass </u></em><em><u>of </u></em><em><u>the </u></em><em><u>object </u></em><em><u>is </u></em><em><u>1</u></em><em><u>1</u></em><em><u>.</u></em><em><u>2</u></em><em><u> </u></em><em><u>Kg.</u></em>
Hope you could get an idea from here.
Doubt clarification - use comment section.
False. C + O --> CO not CO2. Carbonmonoxide
It would <span>keep rolling without slowing down if no friction acted upon it.
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or one hailstone we have;
Force = Mass X acceleration = 0.005kg x 9.8.} This is when the hailstone is not inclined at an angle.
When the hailstone is inclined at an angle of 45, then the component of force along the glass window will be F =0.005kg x 9.8 x sin45= 0.005kg x 9.8 x 0.707= 0.0346N.
Therefore, total force for the 500 hailstones would be 500x0.0346N=17.32N
This force is acting on an area equal to 0.600m2
Pressure = Force per unit area = 17.32N/0.600m2 = 28.9Pa