All categories

3 years ago

For a spherical mirror, the focal length is equal to ____ the radius of curvature of the mirror.

Physics

1 answer:

maksim [4K]3 years ago

4 0

The focal length is equal to one-half the radius of curvature of the mirror.

You might be interested in

A mass M tied to a light string is moving in a vertical circle. The tension in the string at the top is TT and TB at the bottom

natita [175]

Answer:

Explanation:

Tension provides centripetal force in the circular motion . In circular motion work done by force = torque x angle

torque is zero as , centripetal force passes through axis of rotation that is center.

So work done by centripetal force = 0

So work done by tension on M = 0

5 0

3 years ago

Which stars have the lowest absolute brightness?

Finger [1]

Answer:

DWARFS

Explanation:

3 0

3 years ago

Read 2 more answers

What is transmitted by all waves

Nesterboy [21]

<h3>Answer;</h3>

Energy

<h3>Explanation;</h3>

A wave is a transmission of disturbance from one point to another. All waves involve transmission of energy from one point called the source to another point.
Waves describes various ways in which energy can be transferred from a point source.
In electromagnetic waves, for instance, energy transmission occurs as a result of vibrations of electric and magnetic fields.
In mechanical waves energy transmission is as a result of vibration of particles in the medium used. For example in sound waves, energy is transferred through vibration of particles of air or particles of a solid or medium through which sound travels through.

8 0

3 years ago

Read 2 more answers

A gazelle is running at 17.46 m/s. He sees a lion and accelerates at -1.49 m/s/s,

Vsevolod [243]

Answer:

V=21.0211m/s

Explanation:

Use V=vi+at

So, V=17.46m/s+(1.49m/ $s^{2}$ )(2.39s)= 21.0211m/s

5 0

2 years ago

Read 2 more answers

Please help me guys never mind the calculations

vlada-n [284]

The shape is connected in parallel so;

5.1) Ans;

$\frac{1}{R} = \frac{1}{R1} + \frac{1}{R2} \\ \frac{1}{R} = \frac{1}{2} + \frac{1}{3} \\ \frac{1}{R} = \frac{3 + 2}{6} = \frac{5}{6} \\ R = \frac{6}{5} = 1.2 \: \: ohm$

5.2) Ans;

$\frac{1}{R} = \frac{1}{R1} + \frac{1}{R2} \\ \frac{1}{R} = \frac{1}{8} + \frac{1}{10} \\ \frac{1}{R} = \frac{5 + 4}{40} = \frac{9}{40} \\ R = \frac{40}{9} = 4.4 \: \: ohm$

I hope I helped you^_^

7 0

3 years ago