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Alinara [238K]
3 years ago
9

PLS HELP ILL MARK AS BRAINLIST AND FOLLOW U

Mathematics
1 answer:
aleksandrvk [35]3 years ago
7 0

Answer:

No

Step-by-step explanation:

For the calculation for triangle area is wrong

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How to write 8 21/40 as a decimal
jenyasd209 [6]

Answer: 8.525



Step-by-step explanation:


8 0
4 years ago
Solve for x<br> 2(x + 4) = -6<br> x=
polet [3.4K]

Answer:

Step-by-step explanation:

here you go mate :)

step 1

2(x + 4) = -6  solving for x

step 2

2(x + 4) = -6  simplify by distributing

2x+8=-6

step 3

2x+8=-6  subtract 8

2x=-14

step 4

2x=-14  look for the number that can divide them both like 2

2x/2=-14/2

answer

x=-7

4 0
3 years ago
What is the interquartile range of this set of data? 15, 19, 20, 25, 31, 38, 41
Irina18 [472]
First, you have to find the median, which is the number in the middle: 25

Then cut the data in half by the median, so your new data sets are
15,29,20
    and 
31,38,41

Now you find the median of both of those sets, which is 29 and 38.

The interquartile range is the difference between the numbers, so 38-29 = 9.
8 0
4 years ago
PLEASE HELP ASAP!!
Nitella [24]

Answer:

The radius of a sphere is 2 millimeters

The surface area of a sphere is 50.24 square millimeters.

The circumference of the great circle of a sphere is 12.56  millimeters.

Step-by-step explanation:

<u><em>Verify each statement</em></u>

case A) The radius of a sphere is 8 millimeters

The statement is false

we know that

The volume of the sphere is equal to

V=\frac{4}{3}\pi r^{3}

we have

V=100.48/3\ mm^{3}

\pi =3.14

substitute and solve for r

100.48/3=\frac{4}{3}(3.14)r^{3}

r^{3}=(100.48)/(4*3.14)

r=2\ mm    

case B) The radius of a sphere is 2 millimeters

The statement is True

(see the case A)

case C) The circumference of the great circle of a sphere is 9.42 square millimeters  

The statement is false

The units of the circumference is millimeters not square millimeters

The circumference is equal to

C=2\pi r

we have

r=2\ mm  

\pi =3.14

substitute

C=2(3.14)(2)

C=12.56\ mm

case D) The surface area of a sphere is 50.24 square millimeters.

The statement is True

Because

The surface area of the sphere is equal to

SA=4\pi r^{2}

we have

r=2\ mm  

\pi =3.14

substitute

SA=4(3.14)(2)^{2}

SA=50.24\ mm^{2}

case E)  The circumference of the great circle of a sphere is 12.56  millimeters.  

The statement is true

see the case C

case F) The surface area of a sphere is 25.12 square millimeters

The statement is false

because the surface area of the sphere is SA=50.24\ mm^{2}

see the case D

7 0
3 years ago
Read 2 more answers
You are making a poster to support your friend for homecoming. Your original photo is 4 inches by 6 inches. You want the photo o
iris [78.8K]

Answer: i think it is  3456

Step-by-step explanation:

6 0
3 years ago
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