You have two resistors with the same cross sectional area and resistivity. Resistor A has length L1 and resistor B has length L2
1 answer:
Answer:
Explanation:
Given
Resistor A has length
and Resistor B has Length
and Resistance is given by
Considering and A to be constant thus
because
(a)When they are connected in series
As the current in series is same and power is
therefore as R is greater for second resistor
(b)if they are connected in Parallel
In Parallel connection Voltage is same
resistance of 2 is greater than 1 thus Power delivered by 1 is greater than 2
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Answer:
The fraction fraction of the final energy is stored in an initially uncharged capacitor after it has been charging for 3.0 time constants is
Explanation:
From the question we are told that
The time constant
The potential across the capacitor can be mathematically represented as
Where is the voltage of the capacitor when it is fully charged
So at
Generally energy stored in a capacitor is mathematically represented as
In this equation the energy stored is directly proportional to the the square of the potential across the capacitor
Now since capacitance is constant at
The energy stored can be evaluated at as
Hence the fraction of the energy stored in an initially uncharged capacitor is