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tankabanditka [31]

3 years ago

7

You have two resistors with the same cross sectional area and resistivity. Resistor A has length L1 and resistor B has length L2

. Assume L2 > L1. If the resistors are connected in series with a battery, which resistor has the most power delivered to it? Explain. b: If they are connected in parallel with a battery, which resistor has the most power delivered to it? Explain.

1 answer:

oee [108]3 years ago

8 0

Answer:

Explanation:

Given

Resistor A has length $L_1$

and Resistor B has Length $L_2$

and Resistance is given by

$R=\frac{\rho L}{A}$

Considering $\rho$ and A to be constant thus

$R_2>R_1$ because $L_2>L_1$

(a)When they are connected in series

As the current in series is same and power is $i^2R$

therefore $P_2>P_1$ as R is greater for second resistor

(b)if they are connected in Parallel

In Parallel connection Voltage is same

$P=\frac{V^2}{R}$

resistance of 2 is greater than 1 thus Power delivered by 1 is greater than 2

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zavuch27 [327]

Answer:

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3 0

3 years ago

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Answer:

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3 years ago

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Umnica [9.8K]

Answer:

Β. 16 με

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Data provided in the question

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4 0

4 years ago

Any one any kind of clue on this please need help

devlian [24]

I honestly think it is B, if not I'm sorry for the incorrect answer, but B seems to be the only one to make sense

6 0

3 years ago