I believe the answer is A
Double the friction of the object
Kc = 3.2
The chemical equation is
2H2S ⇌ 2H2 + S2
The equilibrium constant expression is
<em>K</em>c ={[H2]^2[S2]}/[H2S]^2
1. Calculate the <em>equilibrium concentrations</em> of each component
[H2] = (4.0 mol)/(4.0 L) = 1.0 mol/L
[S2] = (0.80 mol)/(4.0 L) = 0.20 mol/L
[H2S] = (1.0 mol)/(4.0 L) = 0.25 mol/L
2. Calculate the value of the <em>equilibrium constant</em>
<em>K</em>c = (1.0^2 x 0.20)/0.25^2 = 3.2
Answer:
não sei......................
See Figure 4 below.
1. Draw a 7-carbon chain and number the carbon atoms (<em>Figure 1</em>).
2. Insert a triple bond between atoms 5 and 6 (<em>Figure 2</em>).
3. Attach a phenyl group to atom 3 (<em>Figure 3</em>).
4. Attach a Br to atom 1 (Figure 4).
And you have your structure.
<em>Note</em>: The C≡C triple bond takes <em>priority</em> in the naming, so we must number the chain from the other end. The correct name is
<em>7-bromo-5-phenylhept-2-yne </em>(all one word).