1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
DiKsa [7]
3 years ago
9

For an investigation, a teacher dropped a metal bolt into a container of maple syrup and asked students to remove the bolt witho

ut touching the syrup. The students first tried to use a strong magnet to remove the bolt, but it remained on the bottom of the container. They finally poured the syrup into another container to get the bolt out. Which of these best describes the bolt’s physical properties?
A.
The bolt is magnetic and less dense than the maple syrup.

B.
The bot is non magnetic and less dense than the maple syrup.

C.
The bolt is non magnetic and more dense than the maple syrup.

D.
The bolt is magnetic and has the same density as the maple syrup.

Physics
1 answer:
Aneli [31]3 years ago
6 0

<em>Choice-C</em> is the right one.

-- The bolt didn't react to the magnet, and just laid there.  That tells you that the bolt was made of a non-magnetic material.

-- The bolt didn't float. It went straight to the bottom.  That tells you that it's more dense than the fluid around it.

You might be interested in
What does the w mean in w=fxd
Volgvan

Answer:

here w means work done as we can see that it is the formula for work done where f is force and d is distance travelled. Hope it helped :-)

Explanation:

8 0
3 years ago
Read 2 more answers
2. A car accelerates down the road. What is the "reaction" to the tires pushing on the road?
Artist 52 [7]
The answer would be friction
7 0
3 years ago
An infinite conducting cylindrical shell of outer radius r1 = 0.10 m and inner radius r2 = 0.08 m initially carries a surface ch
irinina [24]

Answer:

a) \sigma_{\rm in} = -2.18~{\rm \mu C/m^2}

b) \sigma_{\rm out}= 1.12~{\rm \mu C/m^2}

c) E = \frac{\sigma(r_1 + r_2)}{\epsilon_0 r}

Explanation:

Before the wire is inserted, the total charge on the inner and outer surface of the cylindrical shell is as follows:

Q_{\rm in} = \sigma A_{\rm in} = \sigma(2\pi r_1 h) = (-0.35)(2\pi (0.08) h) = -0.175h~{\rm \mu C}

Q_{\rm out} = \sigma A_{\rm out} = \sigma(2\pi r_2 h) = (-0.35)(2\pi (0.1) h) = -0.22h~{\rm \mu C}

Here, 'h' denotes the length of the cylinder. The total charge of the cylindrical shell is -0.395h μC.

When the thin wire is inserted, the positive charge of the wire attracts the same amount of negative charge on the inner surface of the shell.

Q_{\rm wire} = \lambda h = 1.1h~{\rm \mu C}

a) The new charge on the inner shell is -1.1h μC. Therefore, the new surface charge density of the inner shell can be calculated as follows:

\sigma_2 = \frac{Q_{\rm in}}{2\pi r_1h} = \frac{-1.1h}{2\pi r_1 h} = \frac{-1.1}{2\pi(0.08)} = -2.18~{\rm \mu C/m^2}

b) The new charge on the outer shell is equal to the total charge minus the inner charge. Therefore, the new charge on the outer shell is +0.705 μC.

The new surface charge density can be calculated as follows:

\sigma_{\rm out}= \frac{Q_{\rm out}}{2\pi r_2h} = \frac{0.705h}{2\pi r_2 h} = \frac{0.705}{2\pi(0.1)} = 1.12~{\rm \mu C/m^2}

c) The electric field outside the cylinder can be found by Gauss' Law:

\int{\vec{E}d\vec{a} = \frac{Q_{enc}}{\epsilon_0}

We will draw an imaginary cylindrical shell with radius r > r2. The integral in the left-hand side will be equal to the area of the imaginary surface multiplied by the E-field.

E(2\pi r h) = \frac{Q_{\rm enc}}{\epsilon_0}\\E2\pi rh = \frac{\sigma 2\pi (r_1 + r_2)h}{\epsilon_0}\\E = \frac{\sigma(r_1 + r_2)}{\epsilon_0 r}

4 0
3 years ago
an ideal gas system undergoes an adiabatic process in which it expands and does 20 J of work on its environment. how much energy
ehidna [41]

Answer:

Zero.

Explanation:

An adiabatic process is one in which there is no exchange of heat energy. Therefore, in an adiabatic process, heat is neither added to the system not it is removed from the system.

The work done by the gas on the environment is 20 J. This energy is equal to the change in internal energy for an adiabatic process.

Therefore, for an ideal gas to undergo an adiabatic process in which it expands and does 20 J of work on its environment, the heat exchange is zero.

8 0
3 years ago
What is a pattern of motion in the solar system
Julli [10]
All the planets is the answer
3 0
3 years ago
Other questions:
  • Torque can be calculated by multiplying the force (N) applied at 90∘ to the lever arm at a distance (m) from the pivot point (po
    5·1 answer
  • g Two boxes with a mass of 34 kg each are resting on a surface where the coefficient of static friction is LaTeX: \mu_sμ s = 0.4
    14·1 answer
  • ༼ つ ◕_◕ ༽つ༼ つ ◕_◕ ༽つ༼ つ ◕_◕ ༽つ☜(゚ヮ゚☜)(☞゚ヮ゚)☞☜(゚ヮ゚☜)(☞゚ヮ゚)☞( ´・・)ノ(._.`)
    10·2 answers
  • A young lady can paddle a canoe in a lake 7.7 m/s. She paddles downstream in a river whose current is 12.4 m/s. What is the comb
    10·1 answer
  • The densities of the elements K, Ca, Sc, and Ti are 0.86, 1.5, 3.2, and 4.5 g/cm³, respectively. One of these elements crystalli
    8·1 answer
  • A 1000 Kg car traveling at 10 m/s hits the back of a 5000 Kg truck
    12·1 answer
  • At atom whose valence electron shell is nearly full is ________ chemically reactive. a. not b. mildly c. highly d. the name of t
    13·2 answers
  • A quarterback, Patrick, throws a football down the field in a long arching trajectory to wide receiver, Tyreek. The football and
    8·1 answer
  • What is the mass of an object that has a weight of 110N ?
    15·1 answer
  • Who was the scientist who gave us the laws of motion?.
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!