... find length
(way 1) determine acceleration using force
only force act on skier is mg vertically. spilt vector we get force along the incline = mgsin(10) and f= ma so
ma = mgsin(10) or a = gsin(10)
a (along the incline)= gsin(10) = 10sin(10) = 1.74
v^2 = u^2 + 2as
15^2 = 3^2 + 2(1.74)s
s = 62.06 m
(way 2) using conservation of energy
energy (KE+PE) on top = energy at bottom
0.5m3^2 + mgh = 0.5m15^2 +0
h (height of incline) = (112.5 - 4.5)/10 = 19.8 m
length of incline = h/sin(10) = 62.2 m ; trigonometry
... find time
s = (u+v)t/2
t = 2s/(u+v) = 2(62.2)/(3+15) = 6.91 s
Answer:
y = 52.44 10⁻⁶ m
Explanation:
It is Rayleigh's principle that two points are resolved if the maximum of the diffraction pattern of one matches the minimum the diffraction pattern of the other
Based on this principle we must find the angle of the first minimum of the diffraction expression
a sin θ= m λ
The first minimum occurs for m = 1
sin θ = λ / a
Now let's use trigonometry the object is a distance L = 0.205 m
tan θ = y / L
Since the angles are very small, let's approximate
tan θ = sin θ/cos θ = sin θ
sin θ = y / L
We substitute in the diffraction equation
y / L = λ / a
y = λ L / a
Let's calculate
y = 550 10⁻⁹ 0.205 / 2.15 10⁻³
y = 52.44 10⁻⁶ m
