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love history [14]
3 years ago
5

Dimethyl sulfoxide [(ch3)2so], also called dmso, is an important solvent that penetrates the skin, enabling it to be used as a t

opical drug-delivery agent. calculate the number of c, s, h, and o atoms in 7.14 × 103 g of dimethyl sulfoxide.
Chemistry
1 answer:
Bas_tet [7]3 years ago
4 0

The molecular formula of dimethyl sulfoxide is (CH_{3})_{2}SO. Molar mass of dimethyl sulfoxide is 78.13 g/mol. Calculate number of moles as follows:

n=\frac{m}{M}=\frac{7.14\times 10^{3} g}{78.13 g/mol}=91.38 mol

From the molecular formula, 1 mole of dimethyl sulfoxide contains 2 moles of Carbon, 6 moles of Hydrogen, 1 mole of Sulfur and 1 mole of oxygen.

Thus, 91.38 moles of dimethyl sulfoxide will have:

Carbon :

n_{C}=2\times 91.38 moles=182.77 moles

Hydrogen:

n_{H}=6\times 91.38 moles=548.28 moles

Sulfur:

n_{S}=1\times 91.38 moles=91.38 moles

Oxygen:

n_{O}=1\times 91.38 moles=91.38 moles

Since, 1 mole of an element equals to 6.023\times 10^{23} atoms thus, number of atoms can be calculated as:

Carbon:

1 mole\rightarrow 6.023\times 10^{23} atoms

Thus,

182.77 moles\rightarrow 182.77\times 6.023\times 10^{23} atoms=1.10\times 10^{26} atoms

Hydrogen:

1 mole\rightarrow 6.023\times 10^{23} atoms

Thus,

548.28 moles\rightarrow 548.28\times 6.023\times 10^{23} atoms=3.30\times 10^{26} atoms

Sulfur:

1 mole\rightarrow 6.023\times 10^{23} atoms

Thus,

91.38 moles\rightarrow 91.38\times 6.023\times 10^{23} atoms=5.50\times 10^{25} atoms

Oxygen:

1 mole\rightarrow 6.023\times 10^{23} atoms

Thus,

91.38 moles\rightarrow 91.38\times 6.023\times 10^{23} atoms=5.50\times 10^{25} atoms

Therefore, number of C, S, H and O atoms are 1.10\times 10^{26}, 5.50\times 10^{25}, 3.30\times 10^{26} and 5.50\times 10^{25} atoms respectively.

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Answer:

The pH is equal to 4.41

Explanation:

Since HClO is a weak acid, its dissociation in aqueous medium is:

                HClO   ⇄   ClO-  +  H+

start:          0.05            0         0

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As it is a weak acid it dissociates very little, in its ClO- and H + ions, so the change is negative, where x is a degree of dissociation.

the acidity constant when equilibrium is reached is equal to:

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clearing the x and calculating its value we have:

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the pH can be calculated by:

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I hope this helps.  Let me know if anything is unclear.
7 0
3 years ago
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