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love history [14]
3 years ago
5

Dimethyl sulfoxide [(ch3)2so], also called dmso, is an important solvent that penetrates the skin, enabling it to be used as a t

opical drug-delivery agent. calculate the number of c, s, h, and o atoms in 7.14 × 103 g of dimethyl sulfoxide.
Chemistry
1 answer:
Bas_tet [7]3 years ago
4 0

The molecular formula of dimethyl sulfoxide is (CH_{3})_{2}SO. Molar mass of dimethyl sulfoxide is 78.13 g/mol. Calculate number of moles as follows:

n=\frac{m}{M}=\frac{7.14\times 10^{3} g}{78.13 g/mol}=91.38 mol

From the molecular formula, 1 mole of dimethyl sulfoxide contains 2 moles of Carbon, 6 moles of Hydrogen, 1 mole of Sulfur and 1 mole of oxygen.

Thus, 91.38 moles of dimethyl sulfoxide will have:

Carbon :

n_{C}=2\times 91.38 moles=182.77 moles

Hydrogen:

n_{H}=6\times 91.38 moles=548.28 moles

Sulfur:

n_{S}=1\times 91.38 moles=91.38 moles

Oxygen:

n_{O}=1\times 91.38 moles=91.38 moles

Since, 1 mole of an element equals to 6.023\times 10^{23} atoms thus, number of atoms can be calculated as:

Carbon:

1 mole\rightarrow 6.023\times 10^{23} atoms

Thus,

182.77 moles\rightarrow 182.77\times 6.023\times 10^{23} atoms=1.10\times 10^{26} atoms

Hydrogen:

1 mole\rightarrow 6.023\times 10^{23} atoms

Thus,

548.28 moles\rightarrow 548.28\times 6.023\times 10^{23} atoms=3.30\times 10^{26} atoms

Sulfur:

1 mole\rightarrow 6.023\times 10^{23} atoms

Thus,

91.38 moles\rightarrow 91.38\times 6.023\times 10^{23} atoms=5.50\times 10^{25} atoms

Oxygen:

1 mole\rightarrow 6.023\times 10^{23} atoms

Thus,

91.38 moles\rightarrow 91.38\times 6.023\times 10^{23} atoms=5.50\times 10^{25} atoms

Therefore, number of C, S, H and O atoms are 1.10\times 10^{26}, 5.50\times 10^{25}, 3.30\times 10^{26} and 5.50\times 10^{25} atoms respectively.

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If you mean what group of elements react the most, the answer is the alkali metals and the halogens because they both only either need to gain or lose one electron. If you mean the most reactive element, it would be fluorine because it has the most electronegativity.

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slega [8]

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m_{HgCl_2}=42.7gHgCl_2

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

HgSO_4+2NaCl\rightarrow HgCl_2+Na_2SO_4

In such a way, the mercury II sulfate (molar mass 296.65g/mol) is in a 1:1 molar ratio with the mercury II chloride (molar mass 271.52g/mol), for that reason the stoichiometry to find mass in grams of mercury II chloride turns out:

m_{HgCl_2}=46.6gHgSO_4*\frac{1molHgSO_4}{296.65 gHgSO_4}*\frac{1molHgCl_2}{1molHgSO_4} *\frac{271.52gHgCl_2}{1molHgCl_2} \\\\m_{HgCl_2}=42.7gHgCl_2

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