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Andre45 [30]
3 years ago
14

Propanoic acid fromula​

Chemistry
1 answer:
Romashka [77]3 years ago
8 0

Answer:

C₃H₆O₂

Explanation:

Propionic acid is a colorless liquid with a sharp rancid odor. Produces irritating vapor. (USCG, 1999)

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If I need 2.2 moles of CO2 , and I have excess Fe2O3 , how many moles of C do I need?
olchik [2.2K]

Answer:

0.733 mol.

Explanation:

  • From the balanced equation:

<em>2Fe₂O₃ + C → Fe + 3CO₂,</em>

It is clear that 1.0 moles of Fe₂O₃  react with 1.0 mole of C to produce 1.0 mole of Fe and 3.0 moles of CO₂.

  • Since Fe₂O₃ is in excess, C will be the limiting reactant.

<u><em>Using cross multiplication:</em></u>

1.0 mole of C produces → 3.0 moles of CO₂, from the stichiometry.

??? mole of C produces → 2.2 moles of CO₂.

∴ The no. of moles of C needed to produce 2.2 moles of CO₂ = (1.0 mole of C) (2.2 mole of CO₂) / (3.0 mole of CO₂) = 0.733 mol.

6 0
2 years ago
PLEASE HELP
morpeh [17]
<span>conductor because it conducts the electrons</span><span />
6 0
3 years ago
Read 2 more answers
Which of the following sets of elements could replace the generic "X" symbol with their own to produce a valid dot notation for
Vsevolod [243]

Answer:

a

Explanation:

Because of their valence electron

Carbon, Silicon and germanium has 4 as their valence electron

5 0
1 year ago
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When butane burns completely, only water and carbon dioxide gas are produced. If 11.6 g of butane and 40.0 L of oxygen at 22.0o
Angelina_Jolie [31]

19.7 litre volume of carbon dioxide gas at 22.0o C and 102 kPa can be collected over water.

<h3>What is vapour pressure?</h3>

Vapour pressure is a measure of the tendency of a material to change into the gaseous or vapour state, and it increases with temperature.

Moles of Butane = mass in grams / molar mass = 11.6 / 58.12 = 0.2

Volume of O_2 (V) = 40 liter

Temperature (T) = 22°C = 22 + 273 = 295 K

Pressure (P) = 102 kPa = 102 / 101.325 = 1.007 atm

Moles of O_2 (n) can be calculated by ideal gas equation.

PV = nRT

n = 1.007 40 ÷ 0.0821 295 = 1.663

Balanced chemical reaction;

2C_4H_10 + 13O_2 ---> 8CO_2 + 10H_2O

From reaction;

13 moles O_2 require 2 moles C_4H_10

So, 1.663 moles O_2 will require = 2 x 1.663 ÷13 = 0.256 moles of C_4H_10

Thus C_4H_10 is a limiting reagent. So it will drive the yield of CO_2.

Moles of CO_2 produced = (8/2) 0.2 = 0.8 moles

Pressure of CO_2 (P) = 102 - 2.24 = 99.76 kPa = 99.76  ÷ 101.325 = 0.985 atm

Applying the ideal gas equation for CO_2,

PV = nRT

0.985 V = 0.8 0.0821 x 295

V = 19.7 liter

The volume of CO_2 produced = 19.7 liter.

Learn more about the vapour pressure here:

brainly.com/question/25699778

#SPJ1

5 0
1 year ago
What happens when you mix hydrogen and oxygen?
Lerok [7]
What happens is it makes water
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3 years ago
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