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2 years ago

Which projectiles will be visibly affected by air resistance when they fall?

Physics

1 answer:

leva [86]2 years ago

8 0

Answer:

Balloon, leaf

Explanation:

Objects that are light and have a relatively large surface that Is affected by the friction with air.

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Is a vector necessarily changed if it is rotated through an angle ?Explain

gavmur [86]

Yes, since it depends on the normal and resultant

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2 years ago

A 0.22-caliber handgun fires a 27-g bullet at a velocity of 755 m/s. is the wave nature of matter significant for bullets?

Neporo4naja [7]

All matter can exhibit wave-like behavior, but the question asks if it is significant. A bullet is a very, very large object compared to the light wave-particles where the wave nature is typically observed. So for an object of this magnitude, it is insignificant.

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3 years ago

A mass of 1.00×10−6 μkg is the same as

tankabanditka [31]

I'm not sure but I know u is 10^6

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2 years ago

Calculate the total displacement of a mouse walking along a ruler, if it begins at the x=5cm, and then does the following: It wa

Lana71 [14]

To begin, the mouse walks from 5 to 12 cm, for a displacement of 7 cm. Next, it walks 8 cm in the opposite direction, for a total displacement of (7 + [-8]) or (-1) cm. This leaves the mouse on 4 cm, and then it walks from there to the 7cm location, for a displacement of 7-4 or +3 cm. Adding 3cm to -1cm gives a final displacement of +2cm.

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2 years ago

How high would you have to lift a 1000kg car to give it a potential energy of:

Elza [17]

Given parameters:

Mass of the car = 1000kg

Unknown:

Height = ?

To find the heights for the different amount potential energy given, we need to understand what potential energy is.

Potential energy is the energy at rest due to the position of a body.

It is mathematically expressed as:

P.E = mgh

m is the mass

g is the acceleration due to gravity = 9.8m/s²

h is the height of the car

Now the unknown is h, height and we make it the subject of the expression to make for easy calculation.

h = $\frac{P.E }{mg}$

For 2.0 x 10³ J;

h = $\frac{2000}{1000 x 9.8}$ = 0.204m

For 2.0 x 10⁵ J;

h = $\frac{200000}{9.8 x 1000}$ = 20.4m

For 1.0kJ = 1 x 10³J;

h = $\frac{1000}{9.8 x 1000}$ = 0.102m

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2 years ago