No, there is significant difference in the use of e readers by different age groups.
Given sample 1 ( 29 years old) 
=628, 
=7%, sample 2( 30 years old)
=2309, 
=0.11.
We have to first form hypothesis one null hypothesis and other alternate hypothesis.
π1-π2=0
π1-π2≠0
α=0.05
Difference between proportions 
The pooled proportion needed to calculate standard error is:
=(44+254)/(628+2309)
=0.10146
The estimated standard error of difference between means is computed using the formula:
=
=
=
=0.01315
Z= Pd-(π1-π2)/
=-0.04-0/0.013
=-3.0769
This test is a two tailed test so the p value for this test is calculated as (using z table)
p value:2 P(Z<-3.0769)
=2*0.002092
=0.004189
P value< significance level of 5%.
Hence there is enough evidence to show the claim that there is a significant difference in the use of e readers by different age groups.
Learn more about hypothesis at brainly.com/question/11555274
#SPJ4
Question is incomplete as it also includes:
Significance level of 5%.
Answer:
68
Step-by-step explanation:
F = 1.8(20)+32 = 68
Answer:
Step-by-step explanation:
we know that
The phrase "Three times the quantity five less than x" means 3 multiplied by the difference of x minus 5
3(x-5)
The phrase "the product of six and x" means the number 6 multiplied by x
6x
therefore
The phrase" Three times the quantity five less than x, divided by the product of six and x" is equal to the quotient of 3(x-5) and 6x
Answer:
(3x+4)(5x+7)
Step-by-step explanation:
15x^2
+41x+28
Factor the expression by grouping. First, the expression needs to be rewritten as 15x^2
+ax+bx+28. To find a and b, set up a system to be solved.
a+b=41
ab=15×28=420
Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 420.
1,420
2,210
3,140
4,105
5,84
6,70
7,60
10,42
12,35
14,30
15,28
20,21
Calculate the sum for each pair.
1+420=421
2+210=212
3+140=143
4+105=109
5+84=89
6+70=76
7+60=67
10+42=52
12+35=47
14+30=44
15+28=43
20+21=41
The solution is the pair that gives sum 41.
a=20
b=21
Rewrite 15x^2
+41x+28 as (15x^2
+20x)+(21x+28).
(15x^2
+20x)+(21x+28)
Factor out 5x in the first and 7 in the second group.
5x(3x+4)+7(3x+4)
Factor out common term 3x+4 by using distributive property.
(3x+4)(5x+7)
Answer: 6x^2-xy-y^2.
Tell me if you want step by step!!
Hope this helped. :)
