2you suppose to multiplie the lenghts to the base
To get better at 12's:
Write down on your paper your 1's facts in column skip 5 and 11 going to 14 (a vertical line - line that goes up and down). To the right of that column, write your two's facts 0 to 8 and repeat again. Then you will have your 12's! Should look as follows
12's:
0 0 = 12 x0
1 2 = 12 x1
2 4 = 12 x2
3 6 = 12 x3
4 8 = 12 x4
6 0 = 12 x5
7 2 = 12 x6
8 4 = 12 x7
9 6 = 12 x8
10 8 = 12 x9
12 0 = 12 x10
13 2 = 12 x 11
14 4 = 12 x 12
The answer to the question is D
Writing algebraic expressions
Answer:
There is no possible triangles
Step-by-step explanation:
\frac{\sin A}{a}=\frac{\sin B}{b}
a
sinA
=
b
sinB
From the reference sheet (reciprocal version).
\frac{\sin O}{58}=\frac{\sin 52}{13}
58
sinO
=
13
sin52
Plug in values.
\sin O=\frac{58\sin 52}{13}\approx 3.5157403
sinO=
13
58sin52
≈3.5157403O=\sin^{-1}(3.5157403)= \text{ERROR}
O=sin
−1
(3.5157403)=ERROR
Sine cannot be greater than 1.
{No Possible Triangles}
No Possible Triangles
{}
{}
