A sample gas initially occupies 3.35

Fe2o3(s)+3co(g)→2fe(s)+3co2(g) in a reaction mixture containing 189 g fe2o3 and 63.0 g co, co is the limiting reactant. part a c

vfiekz [6]

<span>69.3 g First, determine the molar masses involved: Atomic weight iron = 55.845 Atomic weight carbon = 12.0107 Atomic weight oxygen = 15.999 Molar mass Fe2O3 = 2 * 55.845 + 3 * 15.999 = 159.687 g/mol Molar mass CO = 12.0107 + 15.999 = 28.0097 g/mol Determine how many moles of each reactant we have Moles Fe2O3 = 189 g / 159.687 g/mol = 1.18356535 mol Moles CO = 63.0 g / 28.0097 g/mol = 2.249220806 mol For every mole of Fe2O3, we need 3 moles of CO. So let's see how many moles of Fe2O3 is consumed by dividing moles CO by 3. 2.249220806 mol / 3 = 0.749740269 mol So we'll be consuming 0.749740269 moles of Fe2O3, subtract that from what we started with 1.18356535 mol - 0.749740269 mol = 0.433825081 mol Now multiply by the molar mass of Fe2O3 0.433825081 mol * 159.687 g/mol = 69.27622574 g Rounding to 3 significant figures gives 69.3 g</span>

4 0

3 years ago

How many joules are required to completely convert 5.0 g of ice at 0.0 degrees Celsius into water vapor at 100 degrees Celsius?

Mumz [18]

In this question, we have to use 3 equations.
E = mcΔT, E = mlf and E = mlv
E is the energy required (in joules), m is the mass, c is the specific heat capacity of water, ΔT is the change in temperature, lf is the specific latent heat of fusion, and lv is the specific latent heat of vaporization.

Since this question requires the change in temperature during the water state, so the first equation is used, and last 2 equations are for finding the energy required to change state (from ice to water and from water to vapor) (in their mp and bp).

For the specific latent heat and heat capacity, generally they should be given for the question, but we can also look it up online since each substance has their own value.

So the first step is to find the amount of energy needed to convert ice at 0°C to water at 0°C. We can use the second equation. The specific latent heat of fusion of ice is around 334 J kg^-1

E = mlf
E = 5 x 334
E = 1670 J

Next, we have to find the energy required to heat water at 0°C to 100°C. The specific heat capacity of water is around 4.2 J g^-1 °C^-1.

E = mcΔT
E = 5 x 4.2 x (100-0)
E = 2100 J

Then we have to find the amount of heat required to change water at 100°C to water vapor at 100°C. The specific latent heat of vaporization of water is around 2230 J g^-1.

E = mlv
E = 5 x 2230
E = 11150 J

Therefore, to find the final answer, just add up the 3 values for the total energy required.

1670 + 2100 + 11150
= 14920 J

Your final answer should be 14920 joules.

3 0

3 years ago

I WILL GIVE YOU BRAINLIEST!!!

seraphim [82]

Answer:

The second option

6 0

3 years ago

Read 2 more answers

Calculate the volume of air in liters that you might inhale (and exhale) in 12.0 hours. Assume that each breath has a volume of

zloy xaker [14]

Taking into account the rule of three, the volume of air that you inhale (and exhale) in 12.0 hours is 4,384.8 liters.

<h3>Rule of three</h3>

In first place, the rule of three is a way of solving problems of proportionality between three known values and an unknown value, establishing a relationship of proportionality between all of them.

That is, what is intended with it is to find the fourth term of a proportion knowing the other three.

If the relationship between the magnitudes is direct, that is, when one magnitude increases, so does the other (or when one magnitude decreases, so does the other) , the direct rule of three must be applied.

To solve a direct rule of three, the following formula must be followed, being a, b and c known data and x the variable to be calculated:

a ⇒ b

c ⇒ x

So: $x=\frac{cxb}{a}$

<h3 /><h3>Volume of air inhaled and exhaled</h3>

To calculated the volume of air inhaled and exhaled in 12 hours, you know that each breath has a volume of 0.435 liters, and that you are breathing 14 times a minute.

The you can apply the following rule of three: If each breath has a volume of 0.435 liters, 14 breaths have how much volume?

$volume=\frac{14 breathsx0.435 liters}{1 breath}$

<u><em>volume= 6.09 liters</em></u>

So, 14 breaths a minute have a volume of 6.09 liters, this means that in 1 minute you inhale and exhale 6.09 liters.

Now, knowing that 1 hour has 60 minutes, 12 hours has 720 minutes. So you can apply the following rule of three: in 1 minute you inhale and exhale 6.09 liters, in 720 minutes you inhale and exhale how much volume?

$volume=\frac{720 minutesx6.09 liters}{1 minute}$