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Novosadov [1.4K]
4 years ago
15

Water surface waves are _________.. a. longitudinal and perpendicular waves. b. vertical and horizontal waves. c. transverse and

horizontal waves. d. longitudinal and transverse waves
Physics
1 answer:
GuDViN [60]4 years ago
8 0
Water surface waves are examples of waves that are both longitudinal and transverse waves. As the wave travels through the water, a clockwise circles is observed. Therefore, the answer to this item is letter D. All the rest of the choices do not describe the water surface waves. 
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Plz answer plzzz with an correct answer ​
dimaraw [331]
Liquids evaporate faster as they heat up and more particles have enough energy to break away. The particles need energy to overcome the attractions between them. ... Eventually even particles in the middle of the liquid form bubbles of gas in the liquid. At this point the liquid is boiling and turning to gas.
7 0
3 years ago
Your spaceship lands on an unknown planet. To determine the characteristics of this planet, you drop a wrench from 5.00 m above
GenaCL600 [577]

Answer:

g = 15.5 m/s²

Explanation:

In order to find the acceleration due to gravity near the surface of this planet can be calculated by using 2nd equation of motion. The 2nd equation of motion is given as:

h = Vi t + (0.5)gt²

where,

h = height covered by the wrench = 5 m

Vi = Initial Velocity = 0 m/s

t = Time Taken to hit the ground = 0.804 s

g = acceleration due to gravity near the surface of the planet = ?

Therefore,

5 m = (0 m/s)(0.804 s) + (0.5)(g)(0.804 s)²

g = (5 m)/(0.3232 s²)

<u>g = 15.5 m/s²</u>

4 0
4 years ago
What must be true of a force that causes an object to move in a circular motion?
AlladinOne [14]

Before going to answer this question, first we have to understand centripetal force.

The centripetal force is the force which is required to keep the body along its circular path.The direction of the force is along the radius and towards the centre.

Mathematically\ centripetal\ force\ F_{c} =\frac{mv^2}{r}

Here m is the mass of the body,v is the velocity of the body and r is the radius of the circular path.

When a body moves in a circular path,its velocity at any point is the tangent drawn at that point.

As centripetal force acts along the radius, it must be perpendicular to the velocity of the body.

Hence the correct answer to the question is- It acts perpendicular to the velocity and is directed toward the center of the circle.


7 0
3 years ago
Read 2 more answers
The output voltage of a voltage amplifier has been found to decrease by 20% when a load resistance of 1 k is connected. What is
yKpoI14uk [10]

We use the voltage division problem  between the load resistance, amplifier output resistance as

V_{out} = V_{amlifire} \times \frac{R_{load} }{R_{load} + R_{out} }.

Here, V_{out} is the output voltage, V_{amlifire} is the amplifier voltage, R_{load} is the load resistance and R_{out} is the amplifier output resistance.

Therefore,

1-\frac{20}{100} = \frac{1 \ k\Omega }{1 \ k\Omega +R_{out} } \\\\ R_{out} = \frac{1 \ k\Omega }{0.8} -1 \ k\Omega =1250 \Omega -1000 \Omega =250 \Omega.

Thus, the amplifier output resistance is 250 \ \Omega.

4 0
3 years ago
Challenge question: An arrow is placed at 3 centimeters to the left of a converging lens. The image appears at 3 centimeters to
Zanzabum

The focal length of the converging lens based on the arrow placed  3 centimeters to the left and the imaged formed 3 cm to the right is 1.5 cm.

<h3>Focal length of the converging lens</h3>

The focal length of the converging lens is determined by applying the following converging lens formula.

1/f = 1/v + 1/u

where;

  • v is the image distance = 3 cm
  • u is the object distance = 3 cm
  • f is the focal length = ?

1/f = 1/3 + 1/3

1/f = 2/3

f = 3/2

f = 1.5 cm

Thus, the focal length of the converging lens is 1.5 cm.

Learn more about converging lens here: brainly.com/question/22394546

8 0
2 years ago
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