Question

How many molecules of glucose (C6H12O6) are present in 23.3 g of the substance?

Answer 1

Answer:

11

Explanation:

molecules

Answer 2

Answer:

The answer to your question is 7.77 x 10²² molecules of Glucose

Explanation:

Data

Number of molecules = ?

Mass = 23.3 g

Molecular mass of Glucose = 180 g

Avogadro's number = 6.023 x 10²³

Process

1.- Calculate the moles of Glucose in 23.3    

                      180 g ------------------ 1 mol

                       23.3 g ---------------- x

                       x = (23.3 x 1) / 180

                       x = 0.129 moles

2.- Use Avogadro's number to calculate the number of molecules

                        1 mol of Glucose ------------- 6.023 x 10²³ molecules

                      0.129 moles          --------------   x

                         x = (0.129 x 6.023 x 10²³) / 1

                         x = 7.77 x 10²² molecules