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Viktor [21]
3 years ago
11

Through what experiment was Thomson's "plum pudding" model proved inaccurate?

Chemistry
1 answer:
aalyn [17]3 years ago
6 0

Answer:

A

Explanation:

When the particles where shot through gold foil, he found that most of the particles went through. Some scattered in various directions, and a few were even deflected back towards the source.

You might be interested in
Stock nomenclature nh4no3
dedylja [7]

Answer: Stock nomenclature of NH_4NO_3 is ammonium(I) nitrate

Explanation:

Stock nomenclature is used for chemical nomenclature where the oxidation states of some or all of the elements in a compound are indicated  by Roman numerals in parentheses.

For example:

FeCl_2 which has iron in oxidation state of +2 has stock nomenclature of iron(II) chloride.

FeCl_3 which has iron in oxidation state of +3 has stock nomenclature of iron(III) chloride.

Thus the stock nomenclature of NH_4NO_3 is ammonium(I) nitrate as ammonium has oxidation state of +1.

6 0
3 years ago
If 35.50 cm3 of a NaOH solution are required for the complete neutralization of a 25.00cm3 sample of 0.200mol dm-3 H2SO4, what i
Morgarella [4.7K]
In this question, you are given the NaOH volume but asked for concentration. 
Don't forget that for every 1 mol of NaOH there will be 1 mol OH- ion, but for every 1 mol of H2SO4 there will be 2 mol of H- ion.
To neutralize you need the same amount of OH- and H+, so the equation should be:

OH-= H+
<span>35.50cm3 * x*1= 25cm3* 0.2mol/dm3 *2
</span>x= 10/35.5 mol/dm3= 0.2816/dm3
6 0
3 years ago
A chemist makes 940. mL of sodium carbonate (Na_2CO_3) working solution by adding distilled water to 200. mL of a 0.171 m stock
Alexxandr [17]

Answer:

The answer is 0.0698 M

Explanation:

The concentration was prepared by a serial dilution method.

The formula for the preparation I M1V1 = M2V2

M1= the concentration of the stock solution = 0.171 M

V1= volume of the stock solution taken = 200 mL

M2 = the concentration produced

V2 = the volume of the solution produced = 940 mL

Substitute these values in the formula

0.171 × 200 = 490 × M2

34.2 = 490 × M2

Make M2 the subject of the formula

M2 = 34.2/490

M2 = 0.069795

M2 = 0.0698 M ( 3 s.f)

The concentration of the Chemist's working solution to 3 significant figures is 0.0698M

6 0
3 years ago
How many electrons are transferred in the ionic bond between sodium and chlorine in NaCl?
Alexxx [7]

Answer:

1

Explanation:

since Na has one electron in its outer shell it has to give away that one electron in order to obtain a noble gas structure and chlorine needs to obtain one electron also to became a noble gas so it receives the electron that the sodium gave away.

6 0
3 years ago
2Na + 2H20 - 2NaOH + H2
Paul [167]

Answer: B) Ten moles of sodium hydroxide and five moles of hydrogen gas will be produced

Explanation: Got it right on USATestPrep

8 0
2 years ago
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