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2 years ago

Rank in terms of momentum

Physics

1 answer:

eduard2 years ago

7 0

Answer:

See the explanation below,

Explanation:

Momentum is defined as the product of mass by Velocity. In this way, we will replace the following equation in each of the cases.

$P=m*v$

where:

P = momentum [kg*m/s]

m = mass [kg]

v = velocity [m/s]

$P = 10000*0\\P=0$

$P=100*5\\P=500[kg*m/s]$

$P=1200*15\\P=18000[kg*m/s]$

$P=15*1000\\P=15000[kg*m/s]$

From higher to lower momentum

C,D,B,A

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3 years ago

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Answer:

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2 years ago

A bus is moving in astraight line at speed of 25m/s. What time does bus take to cover 5 km

WARRIOR [948]

Answer:

Kinematics

given,

time (t)=100 s, distance (s)=1 km=1000 m

=10m/s (relative speed r.p to bus)

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100

1000

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−V

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10=V

−10

20=V

=20 m/s

Velocity with which scooterist

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Explanation:

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2 years ago

Decreasing the trains velocity will ______ the kinetic energy.<br><br> Decrease or Increase

alex41 [277]

Decreasing the trains velocity will DECREASE the kinetic energy

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3 years ago

Two blocks of masses M 1 and M 2 are connected by a massless string that passes over a massless pulley as shown in the figure. M

stealth61 [152]

The mass M1 is 7.8 kg

Explanation:

Block M1 is hanging on the string while block M2 is on the frictionless ramp.

We have to write the equations of motion for the two blocks.

- For M1, the only two forces acting on it are the force of gravity $M_1 g$ (downward) and the tension in the string T (upward). So we can write

$M_1 g - T = M_1 a$

where

$M_1$ is the mass of the block

$g=9.8 m/s^2$ is the acceleration of gravity

$a$ is the acceleration of the system

- For M2, the only two forces acting on it are the tension in the string T (acting up along the ramp) and the component of the gravity acting down along the ramp, $M_2 g sin \theta$ . So the equation of motion is