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Usimov [2.4K]
3 years ago
11

Rank in terms of momentum

Physics
1 answer:
eduard3 years ago
7 0

Answer:

See the explanation below,

Explanation:

Momentum is defined as the product of mass by Velocity. In this way, we will replace the following equation in each of the cases.

P=m*v

where:

P = momentum [kg*m/s]

m = mass [kg]

v = velocity [m/s]

A)

P = 10000*0\\P=0

B)

P=100*5\\P=500[kg*m/s]

C)

P=1200*15\\P=18000[kg*m/s]

D)

P=15*1000\\P=15000[kg*m/s]

From higher to lower momentum

C,D,B,A

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By definition we have that the final speed is:
 Vf² = Vo² + 2 * a * d
 Where,
 Vo: Final speed
 a: acceleration
 d: distance.
 We cleared this expression the acceleration:
 a = (Vf²-Vo²) / (2 * d)
 Substituting the values:
 a = ((0) ^ 2- (60) ^ 2) / ((2) * (123) * (1/5280))
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 its stopping distance on a roadway sloping downward at an angle of 17.0 ° is:
 First you must make a free body diagram and see the acceleration of the car:
 g = 32.2 feet / sec ^ 2
 a = -77268 (mi / h ^ 2) * (5280/1) (feet / mi) * (1/3600) ^ 2 (h / s) ^ 2
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 Vf² = Vo² + 2 * a * d
 d = (Vf²-Vo²) / (2 * a)
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By equation of motion :

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Answer: 909 m/s

Explanation:

Given

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Thus, the original velocity of the bullet was 909 m/s

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