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ozzi
2 years ago
5

3. How does the wavelength of green different from violet-indigo?​

Physics
1 answer:
grandymaker [24]2 years ago
6 0

Answer:

As the full spectrum of visible light travels through a prism, the wavelengths separate into the colors of the rainbow because each color is a different wavelength. Violet has the shortest wavelength, at around 380 nanometers, and red has the longest wavelength, at around 700 nanometers.

Explanation:

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A car going 22 m/s increases its speed to pass a truck. Five seconds later the car is going 35 m/s. Calculate the acceleration o
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A good thermal conductor ​
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copper and aluminum have the highest thermal conductivity while steel and bronze have the lowest. Heat conductivity is a very important property when deciding which metal to use for a specific application.

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what is the potential energy of the ball when it gets to its maximum height just before falling back to the ground​
love history [14]

Answer:

I will say that the the potential energy will be at its maximum.

Explanation:

potential energy deals with gravity and gravity deals with height, so when a object is in its maximum height it will have the maximum potential energy.  

6 0
3 years ago
A kayakeris paddling 2.50 m/s at an angle of 45° (northeast) and the current is moving 1.25 m/s at an angle of 315° (southeast).
PIT_PIT [208]

The kayaker has velocity vector

<em>v</em> = (2.50 m/s) (cos(45º) <em>i</em> + sin(45º) <em>j</em> )

<em>v</em> ≈ (1.77 m/s) (<em>i</em> + <em>j</em> )

and the current has velocity vector

<em>w</em> = (1.25 m/s) (cos(315º) <em>i</em> + sin(315º) <em>j</em> )

<em>w</em> ≈ (0.884 m/s) (<em>i</em> - <em>j</em> )

The kayaker's total velocity is the sum of these:

<em>v</em> + <em>w</em> ≈ (2.65 m/s) <em>i</em> + (0.884 m/s) <em>j</em>

That is, the kayaker has a velocity of about ||<em>v</em> + <em>w</em>|| ≈ 2.80 m/s in a direction <em>θ</em> such that

tan(<em>θ</em>) = (0.884 m/s) / (2.65 m/s)   →   <em>θ</em> ≈ 18.4º

or about 18.4º north of east.

5 0
3 years ago
What is the minimum speed must a salmon jumping at an angle of 35.2 leave the water in m/s?
yuradex [85]

Height of the waterfall is 0.449 m

its horizontal distance will be 2.1 m

now let say his speed is v with which he jumped out so here the two components of his velocity will be

v_x = vcos35.2 = 0.817 v

v_y = vsin35.2 = 0.576 v

here the acceleration due to gravity is 9.81 m/s^2 downwards

now we can find the time to reach the other end by y direction displacement equation

\Delta y = v_y * t + \frac{1}{2} at^2

-0.449 = 0.576 * v *t - \frac{1}{2}*9.81 * t^2

also from x direction we can say

\Delta x = v_x * t

2.1 = 0.817 v* t

now we have

v* t = 2.57

we will plug in this value into first equation

- 0.449 = 0.576 * 2.57 - 4.905 * t^2

1.93 = 4.905 * t^2

t = 0.63 s

now as we know that

v* t = 2.57

t = 0.63 s

v = \frac{2.57}{0.63}

v = 4.1 m/s

so his minimum speed of jump is 4.1 m/s

8 0
3 years ago
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