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AVprozaik [17]
3 years ago
10

Calculate the molar concentration of the Cl⁻ ions in 0.73 M MgCl2(aq).

Chemistry
1 answer:
Marta_Voda [28]3 years ago
7 0
MgCl2(aq) is an ionic compound which will have the releasing of 2 Cl⁻ ions ions in water for every molecule of MgCl2 that dissolves.
MgCl2(s) --> Mg+(aq) + 2 Cl⁻(aq)
            [Cl⁻] = 0.73 mol MgCl2/1L × 2 mol Cl⁻ / 1 mol MgCl2 = 1.5 M
The answer to this question is [Cl⁻] = 1.5 M
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