Answer:
increase dramatically(a lot).
Explanation:
The core of the earth is way way way hotter than the surface.
The answer to this problem is 11.6m
chegg 2. What pattern did you observe measuring cell voltages with a silver electrode versus with a platinum/H2 electrode There is a difference of -0.786 V in silver
<h3>What is cell voltages ?</h3>
The difference in electric potential between two points, also known as voltage, electric potential difference, electric pressure, or electric tension, is what determines how much labor is required to move a test charge between the two sites in a static electric field. Volt is the name of the derived unit for voltage (potential difference) in the International System of Units. Joules per coulomb, or 1 volt equals 1 joule (of work) for 1 coulomb, is how work per unit charge is stated in SI units (of charge). The quantum Hall and Josephson effect was first employed in the 1990s, and most recently (in 2019), fundamental physical constants have been added for the definition of all SI units and derived units. Power and current were used in the previous SI definition for volt.
To learn more about cell voltages from the given link:
brainly.com/question/18938125
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Answer:
The correct answer is there is a mistake in the calculation. The second law of thermodynamics state that in any spontaneous process there is an increase in the entropy of the universe.
Explanation:
According to the second law a reaction will occur in a system spontaneously if the total entropy of both system and surrounding increases during the reaction.That means in case of spontaneous reaction entropy change is always positive.
But according to the question the reaction H2+F2=2HF is spontaneous in all temperature.So according to the second law of thermodynamics i can say that my classmate made a mistake in calculation that"s why his result for entropy change comes negative.
Answer: pH of resulting solution will be 13
Explanation:
pH is the measure of acidity or alkalinity of a solution.
Moles of
ion = 
Moles of
ion = 

For neutralization:
1 mole of
ion will react with 1 mole of
ion
0.01 mol of
ion will react with =
of
ion
Thus (0.012-0.01)= 0.002 moles of
are left in 20 ml or 0.02 L of solution.
![[OH^-]=\frac{0.002}{0.02L}=0.1M](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D%5Cfrac%7B0.002%7D%7B0.02L%7D%3D0.1M)
![pOH=-log[OH^-]](https://tex.z-dn.net/?f=pOH%3D-log%5BOH%5E-%5D)
![pOH=-log[0.1]=1](https://tex.z-dn.net/?f=pOH%3D-log%5B0.1%5D%3D1)


Thus the pH of resulting solution will be 13