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UkoKoshka [18]
3 years ago
13

Using Circuit 5.1, answer the following questions. Calculate the voltage across the capacitor, assuming that the circuit has bee

n left for a significant amount of time after the power supplies are connected to the other components (this is the initial voltage, vc(0- )). 2. At t = 0, the 10V source is turned off (V=0). Determine how the voltage across the capacitor changes as a function of time. That is, determine an equation for vc (t). a. Find vc(0+) b. Find vc([infinity]) c. Find  d. Write an equation for vc (t) e. Calculate the voltage for the following times: t = , t = 2, t = 3, t = 4, t = 5, t = 6, t = 10,

Engineering
1 answer:
PSYCHO15rus [73]3 years ago
8 0

Complete Question: The complete Question is attached as a file below and the circuit of consideration is contained therein.

Answer:

1) vc(0-) = 6.7 v

2a) vc(0+) = 6.7 v

2b) vc(∞) = 0.825 v

2c) τ = 0.0238775 sec

2d) vc (t) = 0.825 + 5.875 exp(-41.88t) v

e)

vc (τ) = 2.9863 v

vc (2τ) = 1.62 v

vc (3τ) = 1.1175 v

vc (4τ) = 0.9326 v

vc (5τ) = 0.8646 v

vc (6τ) = 0.8396 v

vc (10τ) = 0.8253 v

Explanation:

The circuit analysis and the calculations involved in this question are handwritten and contained in the files attached below.

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Sub heading:

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1 year ago
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..........23÷357=0.0644257703........

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2 years ago
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6 0
1 year ago
A strip ofmetal is originally 1.2m long. Itis stretched in three steps: first to a length of 1.6m, then to 2.2 m, and finally to
andreyandreev [35.5K]

Answer:

strains for the respective cases are

0.287

0.318

0.127

and for the entire process 0.733

Explanation:

The formula for the true strain is given as:

\epsilon =\ln \frac{l}{l_{o}}

Where

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l= length of the member after deformation

l_{o} = original length of the member

<u>Now for the first case we have</u>

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<u>similarly for the second case we have</u>

l= 2.2m

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thus,

\epsilon =\ln \frac{2.2}{1.6}

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thus,

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<u>Now the true strain for the entire process</u>

l=2.5m

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\epsilon =\ln \frac{2.5}{1.2}

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2 years ago
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