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givi [52]
3 years ago
6

13. Which stroke of the four-stroke cycle is shown in the above figure?

Engineering
1 answer:
lianna [129]3 years ago
7 0

Answer:

the cycle is on the power just before the exhaust as both the valves are closed

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Boats float because the gravity is acting down on it and the buoyant force is acting up on the ship.
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Engineering careers. If you want to stay in engineering, your job opportunities are very much linked to your degree type, and you probably know what many of them are already. ...

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You are given a body with no body forces and told that the stress state is given as: ⎡ ⎣ 3αx 5βx2 + αy γz3 5βx2 + αy βx2 0 γz3 0
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This doesn't represent an equilibrium state of stress

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∝ = 1 , β = 1 ,  y = 1

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Attached is the detailed solution is and also the conditions for equilibrium

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4 years ago
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gavmur [86]

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3rd and 4rth

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3 years ago
Suppose that the material to be used in a fuse melts when the current density rises to 459 A/cm2. What diameter of cylindrical w
I am Lyosha [343]

Answer:

The required diameter of the fuse wire should be 0.0383 cm  to limit the current to 0.53 A with current density of 459 A/cm² .

Explanation:

We are given current density of 459 A/cm²  and we want to limit the current to 0.53 A in a fuse wire. We are asked to find the corresponding diameter of the fuse wire.

Recall that current density is given by

j = I/A

where I is the current flowing through the wire and A is the area of the wire

A = πr²

but r = d/2  so

A = π(d/2)²

A = πd²/4

so the equation of current density becomes

j = I/πd²/4

j = 4I/πd²

Re-arrange the equation for d

d² = 4I/jπ  

d = √4I/jπ

d = √(4*0.53)/(459π)

d = 0.0383 cm

Therefore, the required diameter of the fuse wire should be 0.0383 cm  to limit the current to 0.53 A with current density of 459 A/cm² .

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