Question

For the reaction N2 + 3H2 - 2NH3, how many moles of nitrogen are required to produce 9.58 mol of ammonia?

Answer 1

Answer:

3.193 mol

Explanation:

The reaction is

$N_2+3H_2\rightarrow 2NH_3$

We use the stoichiometry in order to find the moles of nitrogen required.

$9.58\ \text{mol of }NH_3\times \dfrac{1\ \text{mol of }N_2}{2\ \text{mol of }NH_3}$

$=3.193\ \text{mol of }N_1$

The amount of nitrogen required is 3.193 mol to produce 9.58 mol of ammonia.