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xz_007 [3.2K]
3 years ago
6

For the reaction N2 + 3H2 - 2NH3, how many moles of nitrogen are required to produce 9.58 mol of ammonia?

Chemistry
1 answer:
V125BC [204]3 years ago
5 0

Answer:

3.193 mol

Explanation:

The reaction is

N_2+3H_2\rightarrow 2NH_3

We use the stoichiometry in order to find the moles of nitrogen required.

9.58\ \text{mol of }NH_3\times \dfrac{1\ \text{mol of }N_2}{2\ \text{mol of }NH_3}

=3.193\ \text{mol of }N_1

The amount of nitrogen required is 3.193 mol to produce 9.58 mol of ammonia.

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Substance X is a compound containing 632mg of manganese and 368mg of oxygen. Substance X is shown
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The empirical formula : MnO₂.

<h3>Further explanation</h3>

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You didn't include the pictures, but the steps for finding the empirical formula are generally the same

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