Answer:
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The empirical formula of this compound is
<u>Given the following data:</u>
<u>Scientific data:</u>
- Molar mass of hydrogen (H) = 1.0 g/mol.
- Molar mass of sulfur (S) = 32 g/mol.
- Molar mass of oxygen (O) = 16 g/mol.
To determine the empirical formula of this compound:
Note: We would assume that the mass of the compound is 100 grams.
Hence, the mass of its constituent elements are:
- Mass of hydrogen (H) = 2.00 grams
- Mass of sulfur (S) = 32.7 grams
- Mass of oxygen (O) = 65.3 grams
Next, we would determine the number of moles of each element by using this formula:
<u>For </u><u>hydrogen</u><u> (</u><u>H</u><u>):</u>
Number of moles = 2.0 moles
<u>For </u><u>sulfur</u><u> (</u><u>S</u><u>):</u>
Number of moles = 1.0 moles
<u>For </u><u>oxygen</u><u> (</u><u>O</u><u>):</u>
Number of moles = 4.0 moles
Empirical formula =
Read more: brainly.com/question/21280037
Answer:
It could be B or C eighter one
Answer:
2HI + K2SO3=>2KI+H2SO3
Explanation:When aqueous hydroiodic acid and aqueous potassium sulfite are mixed the products obtained are potassium iodide and sulfurous acid.Both reactants are ionic compounds and they undergo double replacement reaction.In a double replacement reaction the parts of the ionic compounds are changed.The product is obtained by combinig cation of one compound with anion of other compound.so in above reaction sulfurous acid is obtained which is in gaseous form and potassium iodide is an ionic compound.
Answer:
Solid potassium iodide decomposes into solid potassium and iodide gas.
Explanation:
The answer given has a subscript "2" on the iodine at the start of the equation. Why is the 2 there as a subscript?