Answer: mass of chlorine reacted is 3.18 g
Explanation:
2 K + Cl2 = 2KCl
no. of moles of K = mass / molar mass
= 3.50 / 39
= 0.0897
no. of moles of KCl = mass / molar mass
= 6.67 / 74.5
= 0.0895
no. of moles of Cl2 required = number of moles of KCl / 2
= 0.0895 / 2
= 0.0448 moles
mass of Cl2 required = no. of moles of Cl2 required x molar mass
= 0.0448 x 71
= 3.1808 g ≈ 3.18 g
Therefore mass of chlorine reacted is 3.18 g
<u>Given:</u>
Mass of H2O2 solution = 5.02 g
Mass of H2O2 = 0.153 g
<u>To determine: </u>
The % H2O2 in solution
<u>Explanation:</u>
Chemical reaction-
2H2O2(l) → 2H2O(l) + O2(g)
Mass % of a substance in a solution = (Mass of the substance/Mass of solution) * 100
In this case
% H2O2 = (Mass H2O2/Mass of solution)* 100 = (0.153/5.02)*100 = 3.05%
Ans: % H2O2 in the solution = 3.05%
Properties.....................
The sign of ΔSsys for a solid explosive converts to a gas is positive.
The term used for the measurement of randomness and disorderliness in a system is known as Entropy (S). ΔS calculates the change in entropy and it is positive when entropy increase and negative when entropy decreases.
Entropy increases when heat is added to the system. Addition of heat increases the randomness of the molecules and hence the entropy increases.
When a solid explosive converts to a gas the randomness increases. Explosive causes heat and the solid is converted into gas. The randomness of molecules is maximum in gases thus the entropy increases. The sign of ΔS is positive for this process.
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The molecular formula shows the number of atoms present. The molecular formula of the gas is most likely ClO2.
In terms of gas density and molar mass, the ideal gas equation can be written in the form; PM = dRT
Where;
P = pressure of the gas
M = molar mass of the gas
d = density of the gas
R = molar gas constant
T = temperature of the gas
Making the molar mass of the gas the subject of the formula;
M = dRT/P
d = 2.875 g/L
R = 0.082 atmLmol-1K-1
T = 11°C + 273 = 284 K
P = 750.0 mm Hg or 0.99 atm
Substituting values;
M = 2.875 g/L × 0.082 atmLmol-1K-1 × 284 K/ 0.99 atm
M = 67.6 g/mol
The gas is most likely ClO2.
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