These masses are isotopes. By definition, isotopes of an element have the same number of protons as the given element, but different numbers of neutrons.
Mark Brainliest please
Answer
There are 17 nutrients that essential for the growth of the plants. These nutrients are classified into two categories on the basis of requirement micronutrients (required in less amount) and macronutrient (required in large amount). The three primary nutrients needed for plant growth are nitrogen, phosphorous and potassium.
It's something to do with the weathering process.
Eg. At night it's really cold, and in the day it's really hot.
Because the temperature keeps changing dramatically day in and day out,
the sand dunes start to be sort of hacked or re-shaped, or even formed.
The question is incomplete, the complete question is;
Determine whether each melting point observation corresponds to a pure sample of a single compound or to an impure sample with multiple compounds.
Experimental melting point is BELOW literature value
Experimental melting point is CLOSE to literature value
WIDE melting point range
NARROW melting point range
Answer:
narrow melting point-pure sample of a single compound
experimental melting point is close to literature value-pure sample of a single compound
wide melting point range-impure sample of multiple compounds
experimental melting point is below literature value-impure sample of multiple compounds
Explanation:
The experimental melting point of a pure single compound is sharp and extremely close to the melting point of the substance as recorded in the literature. Usually, a pure substance melts within a narrow range of temperatures.
Impure samples of multiple compounds melt over a range of temperatures. Also if the experimental melting point is well below the record in literature, then the sample is contaminated by other compounds.
The molar concentration of the solution is calculated as follows
find the moles of NaCl used to make the solution
moles = mass/molar mass
mass =7.83 g
molar mass =58.5 g/mol
moles = 7.83 g/ 58.5 g/mol = 0.134 moles
molarity ( concentration in mol/l) = number of moles/volume in liters
volume in liters = 90ml/1000 =0.09 liters
molarity is therefore = 0.134 moles/0.09 L =1.49 M
