Solution :
Energy of photon, E = 6.7 eV
E = 
joule
Kinetic energy, 
Kinetic energy at high speeds
r - 1 = 7130
r = 7130 + 1
r = 7131
![$v^2=C^2\left[1-\left(\frac{1}{7131}\right)^2\right]$](https://tex.z-dn.net/?f=%24v%5E2%3DC%5E2%5Cleft%5B1-%5Cleft%28%5Cfrac%7B1%7D%7B7131%7D%5Cright%29%5E2%5Cright%5D%24)
Δ = 1 - 0.99999999017
= 0.00000000933
Relative mass, 
kg
Answer:
-30 °C
Explanation:
First, we have to calculate the molality (m) of the solution. If the solution is 50% C₂H₆O₂ by mass. It means that in 100 g of solution, the are 50 g of solute (C₂H₆O₂) and 50 g of solvent (water).
The molar mass of C₂H₆O₂ is 62.07 g/mol. The moles of solute are:
50 g × (1 mol / 62.07 g) = 0.81 mol
The mass of the solvent is 50 g = 0.050 kg.
The molality is:
m = 0.81 mol / 0.050 kg = 16 m
The freezing-point depression (ΔT) can be calculated using the following expression.
ΔT = Kf × m = (1.86 °C/m) × 16 m = 30 °C
where,
Kf: freezing-point constant
The normal freezing point for water is 0°C. The freezing point of the radiator fluid is:
0°C - 30°C = -30 °C
Answer:
Michael is heavier.
Explanation:
If Michael is 104 pounds, that is equal to 47 kg.
Erica is 44 kg which is 97 pounds.
104 is greater than 97, and 47 is greater than 44.
Answer: That the storm is moving toward hillville and that residents should be prepared.
Explanation:
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