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klasskru [66]
3 years ago
11

Write a essay on endangered animals

Chemistry
1 answer:
Kay [80]3 years ago
7 0

Answer:

WHATS OOP Lucy???

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The following reaction was carried out in a 2.50 LL reaction vessel at 1100 KK: C(s)+H2O(g)⇌CO(g)+H2(g)C(s)+H2O(g)⇌CO(g)+H2(g) I
Schach [20]

Answer:

Q = 0.144

Explanation:

  • C(s) + H2O(g) ↔ CO(g) + H2(g)

reaction quotient:

  • Q = [H2(g)][CO(g)] / [H2O(g)][C(s)]

∴ [C(s)] = 10.0 mol/2.50 L = 4 M

∴ [H2O(g)] = 16.0 mol/2.50 L = 6.4 M

∴ [CO(g)] = 3.30 mol/2.50 L = 1.32 M

∴ [H2(g)] = 7.00 mol/2.50 L = 2.8 M

⇒ Q = (2.8 M)(1.32 M) / (6.4 M)(4 M)

⇒ Q = 0.144

3 0
4 years ago
In a combustion reaction, one of the reactants is always _______________.
QveST [7]
In a combustion reaction, one of the reactants is always oxygen.
4 0
4 years ago
Read 2 more answers
PLEASE I WILL PUT YOU AS BRAINLIEST, 20 POINTS
fiasKO [112]

Answer:

a light ray will always A light ray will always reflect away from a surface at an angle equal to the angle at which it struck the surface

Explanation:

it sound more formal and just plainly better

8 0
3 years ago
Read 2 more answers
Given:
marusya05 [52]

Answer:

92.6 g.

Explanation:

  • The balanced equation is:

CaC₂ + N₂ → CaCN₂ + C.

  • It is clear that 1.0 mole of CaC₂ reacts with 1.0 mole of N₂ to produce 1.0 mole of CaCN₂ and 1.0 mole of C.
  • We need to calculate the no. of moles of 265.0 g of CaCN₂ produced using the relation:

n = mass / molar mass = (265.0 g) / (80.102 g/mol) = 3.308 mol.

  • We should get the no. of moles of N₂ needed to produce 3.308 mol of CaCN₂.

∵ 1.0 mole of N₂ produces → 1.0 mole of CaCN₂.

<em>∴ 3.308 mole of N₂ produces → 3.308 mole of CaCN₂.</em>

  • Now, we can get the grams of N₂  consumed to produce 265.0 g of CaCN₂:

∴ The grams of N₂ = n x molar mass = (3.308 mole)(28.0 g/mol) = 92.63 g = 92.6 g.

7 0
4 years ago
What are the coefficients of the compounds after balancing the following equation and what type of reaction is this?
Oksana_A [137]

The coefficient of Fe would be 2, the coefficient of Cl2 would be 3, while the coefficient of FeCl2 would be 2.  

The balanced equation of the reaction would be as follows:

2Fe(S) + 3Cl_2 ---> 2FeCl_3(S)

Thus, the coefficients of Fe, Cl2, and FeCl3 respectively would be 2, 3, and 2.

In other words, 2 moles of Fe require 3 moles of Cl2 to produce 2 moles of FeCl3 in a complete reaction.

More on balancing chemical equations can be found here: brainly.com/question/8062886?referrer=searchResults

4 0
3 years ago
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