A skier starts from rest at the top of a 40.8 m hill, skis down a 30 degree incline into a valley, and continues up a 32.5 m hig
1 answer:
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Answer:
The the linear speed (in m/s) of a point on the rim of this wheel at an instant=0.418 m/s
Explanation:
We are given that
Angular acceleration,
Diameter of the wheel, d=21 cm
Radius of wheel, cm
Radius of wheel,
1m=100 cm
Magnitude of total linear acceleration, a=
We have to find the linear speed of a at an instant when that point has a total linear acceleration with a magnitude of 1.7 m/s2.
Tangential acceleration,
Radial acceleration,
We know that
Using the formula
Squaring on both sides
we get
Hence, the the linear speed (in m/s) of a point on the rim of this wheel at an instant=0.418 m/s
Answer:
b. 0.20 m/s.
Explanation:
Given;
initial mass, m = 0.2 kg
maximum speed, v = 0.3 m/s
The total energy of the spring at the given maximum speed is calculated as;
K.E = ¹/₂mv²
K.E = 0.5 x 0.2 x 0.3²
K.E = 0.009 J
If the mass is changed to 0.4 kg
¹/₂mv² = K.E
mv² = 2K.E
Therefore, the maximum speed is 0.20 m/s