1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Paraphin [41]
3 years ago
11

Suppose that you release a small ball from rest at a depth of 0.730 m below the surface in a pool of water. If the density of th

e ball is 0.350 that of water and if the drag force on the ball from the water is negligible, how high above the water surface will the ball shoot as it emerges from the water? (Neglect any transfer of energy to the splashing and waves produced by the emerging ball.)
Physics
1 answer:
Misha Larkins [42]3 years ago
8 0

Answer:

21.8 m

Explanation:

Net force on the ball inside water

= Buoyant force - weight of ball

= mρg - mdg

where ρ is density of water and d is density of ball

= m ( ρ - .35ρ ) g

This force acts on the ball upto distance .73 m so work done by force  will be equal to kinetic energy acquired by the ball.

m ( ρ - .35ρ ) g x .73 = 1/2 mv²

10³ ( 1 - .35 ) x g x .73 = 1/2 mv²

v² = 10³ x .65 x 9.8 x .73 x 2

v²  = 9300

After emerging from water , buoyant force stops acting on it.  

It will stop at height such that

1/2 mv² = mgh

v² = 2gh

h = v² / 2g

9300 / 2 x 9.8

= 21.8 m  

You might be interested in
A car is moving at 19 m/s along a curve on a horizontal plane with radius of curvature 49m.
JulsSmile [24]

Answer:

\mu =0.75

Explanation:

<u>Frictional Force </u>

When the car is moving along the curve, it receives a force that tries to take it from the road. It's called centripetal force and the formula to compute it is:

F_c=m.a_c

The centripetal acceleration a_c is computed as

\displaystyle a_c=\frac{v^2}{r}

Where v is the tangent speed of the car and r is the radius of curvature. Replacing the formula into the first one

F_c=m.\frac{v^2}{r}

For the car to keep on the track, the friction must have the exact same value of the centripetal force and balance the forces. The friction force is computed as

F_r=\mu N

The normal force N is equal to the weight of the car, thus

F_r=\mu .m.g

Equating both forces

\displaystyle \mu .m.g=m.\frac{v^2}{r}

Simplifying

\displaystyle \mu =\frac{v^2}{rg}

Substituting the values

\displaystyle \mu =\frac{19^2}{(49)(9.8)}

\boxed{\mu =0.75}

7 0
3 years ago
A racecar driver steps on the gas, and his racecar travels 20 meters in 2 seconds starting from rest. The acceleration of the ra
givi [52]

Answer:

2.5m/s^2

Explanation:

Step one:

given

distance = 20meters

time = 2 seconds

initial velocity u= 0m/s

let us solve for the final velocity

velocity = distance/time

velocity= 20/2

velocity= 10m/s

v^2=u^2+2as\\\\10^2=0^2+2*a*20\\\\100=40a

divide both sides by 40

a= 100/40\\\\a=10/4\\\\a= 5/2\\\\a= 2.5m/s^2

5 0
3 years ago
the car turned a corner going 10m/s if it took two seconds to turn what is its acceleration is this acceleration​
exis [7]

The acceleration of this car is equal to 5 m/s^2.

<u>Given the following data:</u>

  • Initial velocity = 0 m/s (assuming it's starting from rest).
  • Final velocity = 10 m/s.
  • Time = 2 seconds.

To determine the acceleration of this car:

<h3>How to calculate acceleration.</h3>

In Science, the acceleration of an object is calculated by subtracting the initial velocity from its final velocity and dividing by the time.

Mathematically,  acceleration is given by this formula:

a = \frac{V\;-\;U}{t}

<u>Where:</u>  

  • V is the final velocity.
  • U is the initial velocity.
  • is the time measured in seconds.

Substituting the given parameters into the formula, we have;

a = \frac{10\;-\;0}{2}

Acceleration, a = 5 m/s^2

Read more on acceleration here: brainly.com/question/24728358

6 0
2 years ago
A car travels a distance of 400 m in 5 seconds. Calculate its average velocity.
ikadub [295]

Answer:

80 m/s

Explanation:

x = 400 m

t = 5 s

x = vt,

400 = v(5),

80 = v

5 0
3 years ago
Read 2 more answers
Your mom is making lunch which forces are acting on your mom
N76 [4]

The forces acting on your mom while cooking is Air resistance and the force of friction

<u>Explanation:</u>

<u>1. Air resistance:</u>

  • In simple words, Air resistance can be stated as the type of friction  between the air and the other materials.
  • In this scenario, there will be an air resistance and the air hits the mom while cooking via the doors or windows

<u>2. The force of friction:</u>

  • In simple words, friction can be stated as, the resistance that one surface or object encounters when moving over another.
  • While cooking the food mom would experience the friction since friction is the transfer of heat, and cooking is the process of receiving that heat.

7 0
3 years ago
Read 2 more answers
Other questions:
  • Formula for displacement
    15·1 answer
  • 50 g of liquid Y at 10 Celcius and 200 g of liquid Y at 40Celcius are mixed. Final temperature of the mixture is measured as 15
    12·1 answer
  • Sunlight has its maximum intensity at a wavelength of 4.83 x 10'm; wha energy does this correspond to in e?
    7·1 answer
  • A string is attached to a ball that has a mass of 0.11 kg. A student pulls up on the string so that the ball accelerates upward
    10·1 answer
  • The source of Earth's magnetic field is
    5·2 answers
  • How would the terminal velocity of a piece of tissue paper compare to the terminal velocity of a rock?
    11·1 answer
  • Shoo the fly flaps its wings back and forth 140 times each second. The frequency of the wing flapping is ____ Hz.
    10·1 answer
  • A series circuit has a current of 3 A. The circuit contains a 12 resistor. What is the voltage of the circuit?
    8·2 answers
  • A _____ has to do with the direction of a force​
    14·2 answers
  • What is the pressure exerted by a column of fresh water 10m high<br>(p=1000kg/m3 and g=10m/s)​
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!