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Paraphin [41]
2 years ago
11

Suppose that you release a small ball from rest at a depth of 0.730 m below the surface in a pool of water. If the density of th

e ball is 0.350 that of water and if the drag force on the ball from the water is negligible, how high above the water surface will the ball shoot as it emerges from the water? (Neglect any transfer of energy to the splashing and waves produced by the emerging ball.)
Physics
1 answer:
Misha Larkins [42]2 years ago
8 0

Answer:

21.8 m

Explanation:

Net force on the ball inside water

= Buoyant force - weight of ball

= mρg - mdg

where ρ is density of water and d is density of ball

= m ( ρ - .35ρ ) g

This force acts on the ball upto distance .73 m so work done by force  will be equal to kinetic energy acquired by the ball.

m ( ρ - .35ρ ) g x .73 = 1/2 mv²

10³ ( 1 - .35 ) x g x .73 = 1/2 mv²

v² = 10³ x .65 x 9.8 x .73 x 2

v²  = 9300

After emerging from water , buoyant force stops acting on it.  

It will stop at height such that

1/2 mv² = mgh

v² = 2gh

h = v² / 2g

9300 / 2 x 9.8

= 21.8 m  

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A woman is 160160cm tall. What is the minimum vertical length of a mirror in which she can see her entire body while standing up
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This question is incomplete, the complete question is;

A woman is 160cm tall. What is the minimum vertical length of a mirror in which she can see her entire body while standing upright.

Hint: Consider the ray diagram below, of the rays that enable her to see her feet and the top of her head.

Use what you know about the law of reflection, together with a bit geometry.

The missing Image is uploaded along this answer below.

Answer:

the minimum vertical length of a mirror in which she can see her entire body while standing upright is 80 cm

Explanation:

Given the data in the question and illustrated in the image below,

From image 2;

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AC = CD

since AD = a and AC + CD = A

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DF = FG

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3 years ago
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Answer:

Explanation:

For the first case , the expression for electrostatic force can be given by the following .

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F₁ = 9 F / 16 .

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