Answer:
a) P = 149140[w]; b) 1491400[J]; c) v = 63.06[m/s]
Explanation:
As the solution to the problem indicates, we must convert the power unit from horsepower to kilowatts.
P = 200 [hp]
![200[hp] * 745.7 [\frac{watt}{1 hp}]\\149140[watt]](https://tex.z-dn.net/?f=200%5Bhp%5D%20%2A%20745.7%20%5B%5Cfrac%7Bwatt%7D%7B1%20hp%7D%5D%5C%5C149140%5Bwatt%5D)
Now the power definition is known as the amount of work done in a given time
P = w / t
where:
w = work [J]
t = time [s]
We have the time, and the power therefore we can calculate the work done.
w = P * t
w = 149140 * 10 = 1491400 [J]
And finally, we can calculate the velocity using, the expression for kinetic energy
![E_{k}=w=0.5*m*v^{2}\\ where:\\v = velocity[m/s]\\m=mass=750[kg]\\w=work=1491400[J]\\](https://tex.z-dn.net/?f=E_%7Bk%7D%3Dw%3D0.5%2Am%2Av%5E%7B2%7D%5C%5C%20%20where%3A%5C%5Cv%20%3D%20velocity%5Bm%2Fs%5D%5C%5Cm%3Dmass%3D750%5Bkg%5D%5C%5Cw%3Dwork%3D1491400%5BJ%5D%5C%5C)
The key to solving this problem is to recognize that work equals kinetic energy
![v=\sqrt{\frac{w}{0.5*m}} \\v=\sqrt{\frac{1491400}{0.5*750}} \\v=63.06[m/s]](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B%5Cfrac%7Bw%7D%7B0.5%2Am%7D%7D%20%20%5C%5Cv%3D%5Csqrt%7B%5Cfrac%7B1491400%7D%7B0.5%2A750%7D%7D%20%20%5C%5Cv%3D63.06%5Bm%2Fs%5D)
Answer:
The basic principle on which the electric iron works is that when a current is passed through a piece of wire, the wire heats up. This heat is distributed to the sole (base) plate of the electric iron through conduction.
Answer:
the answer will be C. 4 degrees C
Explanation:
you subtract base meters from peak meters to get 4 meters; then Multiply 6.5 by 4.
Then subtract that total from 30 degrees C
***as altitude increases, temperature decreases***
The Sun is a huge, glowing sphere of hot gas. Most of this gas is hydrogen (about 70%) and helium (about 28%). Carbon, nitrogen and oxygen make up 1.5% and the other 0.5% is made up of small amounts of many other elements such as neon, iron, silicon, magnesium and sulfur.
So typically I would say hydrogen and helium.
Use force (thrust) equals mass times acceleration.
