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3 years ago

Me ayudan doy coronita

Chemistry

1 answer:

lbvjy [14]3 years ago

8 0

Answer:

Explanation:

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Сгорело 6 г угля С. Вычислите массу образовавшегося оксида углерода (IV)<br>просто скажите ответ

skad [1K]

English<span>Сгорело 6 г угля С. Вычислите массу образовавшегося оксида углерода (IV)
просто скажите ответ</span>

7 0

3 years ago

The concentrated sulfuric acid we use in the laboratory is 98.0% sulfuric acid by weight. Calculate the molality and molarity of

timama [110]

Answer : The molarity and molality of the solution is, 18.29 mole/L and 499.59 mole/Kg respectively.

Solution : Given,

Density of solution = $1.83g/cm^3=1.83g/ml$

Molar mass of sulfuric acid (solute) = 98.079 g/mole

98.0 % sulfuric acid by mass means that 98.0 gram of sulfuric acid is present in 100 g of solution.

Mass of sulfuric acid (solute) = 98.0 g

Mass of solution = 100 g

Mass of solvent = Mass of solution - Mass of solute = 100 - 98.0 = 2 g

First we have to calculate the volume of solution.

$\text{Volume of solution}=\frac{\text{Mass of solution}}{\text{Density of solution}}=\frac{100g}{1.83g/ml}=54.64ml$

Now we have to calculate the molarity of solution.

$Molarity=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{volume of solution}}=\frac{98.0g\times 1000}{98.079g/mole\times 54.64ml}=18.29mole/L$

Now we have to calculate the molality of the solution.

$Molality=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Mass of solvent}}=\frac{98.0g\times 1000}{98.079g/mole\times 2g}=499.59mole/Kg$

Therefore, the molarity and molality of the solution is, 18.29 mole/L and 499.59 mole/Kg respectively.

7 0

3 years ago

Anyone help plz <br> And ty

andreyandreev [35.5K]

Answer: do that yourself dip

Explanation:

6 0

3 years ago

How many of sodium (Na) are needed to make 4.5 liters of a 1.5mol/L of Na solution?

Salsk061 [2.6K]

Answer:

Explanation:

First you will find the mole from the molarity and then the desired mass from the mole.

5 0

3 years ago

We are given that when θ = 38.7°, the angle of refraction in the liquid is θ = 26.3°. Thus, from Snell's law, the index of refra

oee [108]

Answer:1.4

Explanation:

Angle of incidence= 38°

Angle of refraction=26.3°

From Snell's law: n= sin i/sinr

sin i= 0.6157

sin r= 0.4430

n= 0.6157/0.4430=1.4

Note, n is dimensionless

5 0

3 years ago

Me ayudan doy coronita ​

Me ayudan doy coronita