Question

Consider two aqueous solutions of NaCl. Solution 1 is 4.00 M and solution 2 is 0.10 M. In what ratio (solution 1 to solution 2) must these solutions be mixed in order to produce a 0.86 M solution of NaCl

Answer 1

Answer:

The ratio of solution 1 to solution 2 is 24.20 to 100.00.

Explanation:

We will mix V₁ (L) of solution 1 with V₂ (L) of solution 2 to get the final solution.

So the mole concentration in the final solution is calculated as below, note that C₁ is the concentration of solution 1, and C₂ is the concentration of solution 2

$[M] = \frac{V_{1} C_{1} +V_{2}C_{2}}{V_{1}+V_{2}} = \frac{4 V_{1} + 0.1 V_{2}}_{V_{1}+V_{2}}}=0.86$

Then we can calculate for the ratio

$\frac{V_{1}}{V_{2}}=\frac{0.86-0.10}{4.00-0.86} =\frac{0.76}{3.14}$ or $\frac{24.20}{100.00}$