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avanturin [10]
3 years ago
10

Consider two aqueous solutions of NaCl. Solution 1 is 4.00 M and solution 2 is 0.10 M. In what ratio (solution 1 to solution 2)

must these solutions be mixed in order to produce a 0.86 M solution of NaCl
Chemistry
1 answer:
Maru [420]3 years ago
6 0

Answer:

The ratio of solution 1 to solution 2 is 24.20 to 100.00.

Explanation:

We will mix V₁ (L) of solution 1 with V₂ (L) of solution 2 to get the final solution.

So the mole concentration in the final solution is calculated as below, note that C₁ is the concentration of solution 1, and C₂ is the concentration of solution 2

[M] = \frac{V_{1} C_{1} +V_{2}C_{2}}{V_{1}+V_{2}} = \frac{4 V_{1} + 0.1 V_{2}}_{V_{1}+V_{2}}}=0.86

Then we can calculate for the ratio

\frac{V_{1}}{V_{2}}=\frac{0.86-0.10}{4.00-0.86}  =\frac{0.76}{3.14} or \frac{24.20}{100.00}

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Andreas93 [3]

Answer:

0.1077 grams

Explanation:

First we will employ the ideal gas law to determine the number of moles of nitrogen gas.

PV=nRT

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V=20L

R=0.08206*L*atm*mol^-1*K^-1

T=323.15 K

Thus, 2atm*20L=n*0.08206*L*atm*mol^-1*K^-1*323.15K

K, atm, and L cancels out. Thus n=2*20mol/0.08206*323.15=1.5 moles

Lastly, we must convert the number of moles to grams. This can be done by dividing the number of moles by the molar mass of nitrogen gas, which is 14 grams.

1.5/14=0.1077 grams

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borishaifa [10]

Answer:

Chemical Formula

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<h3>What is a Food web?</h3>

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finlep [7]

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3 years ago
What is the molarity of a solution made by mixing 75.0 mL of 3.00 M NH₄OH with enough water to give 250. mL of solution?
enyata [817]

Answer:

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