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Elena L [17]
2 years ago
6

2000:$5.00 2015:6.50 what is the change in the cost of the cheeseburger as a percent pls answer ASAP!! plsssssss

Mathematics
1 answer:
Salsk061 [2.6K]2 years ago
3 0
23.18...........................
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An investment firm invested in two companies last year. They invested $11,000 in Company A and made a profit of 24% . They inves
Tema [17]
First off, "whatever%" of "anything" is just (whatever/100) * anything

part A)

so... firm A got 11,000 invested, turned a profit of 24%, how much is 24% of 11000? well (24/100) * 11000

firm B got 14,000 invested, and returned 15% in profits, how much is 15% of 14000?   (15/100) * 14000

part B)

for the amounts above, we get 2640 and 2100 respectively

so, the total profit "amount" is 2640 + 2100 or 4740

the total investement was 11000+14000 = 25000

if 25000 is the 100%, how much is 4740 in percentage?

\bf \begin{array}{ccllll}
amount&\%\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
25000&100\\
4740&x
\end{array}\implies \cfrac{25000}{4740}=\cfrac{100}{x}

solve for "x"
6 0
3 years ago
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In the triangles,BC is congruent to RS and AC is congruent to TS If RT is greater than BA, which correctly compares angles C and
svp [43]
The answer is B i just took the test m∠C < ∠S
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Given the sequence 1/2 ; 4 ; 1/4 ; 7 ; 1/8 ; 10;.. calculate the sum of 50 terms
miv72 [106K]

<u>Hint </u><u>:</u><u>-</u>

  • Break the given sequence into two parts .
  • Notice the terms at gap of one term beginning from the first term .They are like \dfrac{1}{2},\dfrac{1}{4},\dfrac{1}{8} . Next term is obtained by multiplying half to the previous term .
  • Notice the terms beginning from 2nd term , 4,7,10,13 . Next term is obtained by adding 3 to the previous term .

<u>Solution</u><u> </u><u>:</u><u>-</u><u> </u>

We need to find out the sum of 50 terms of the given sequence . After splitting the given sequence ,

\implies S_1 = \dfrac{1}{2},\dfrac{1}{4},\dfrac{1}{8} .

We can see that this is in <u>Geometric</u><u> </u><u>Progression </u> where 1/2 is the common ratio . Calculating the sum of 25 terms , we have ,

\implies S_1 = a\dfrac{1-r^n}{1-r} \\\\\implies S_1 = \dfrac{1}{2}\left[ \dfrac{1-\bigg(\dfrac{1}{2}\bigg)^{25}}{1-\dfrac{1}{2}}\right]

Notice the term \dfrac{1}{2^{25}} will be too small , so we can neglect it and take its approximation as 0 .

\implies S_1\approx \cancel{ \dfrac{1}{2} } \left[ \dfrac{1-0}{\cancel{\dfrac{1}{2} }}\right]

\\\implies \boxed{ S_1 \approx 1 }

\rule{200}2

Now the second sequence is in Arithmetic Progression , with common difference = 3 .

\implies S_2=\dfrac{n}{2}[2a + (n-1)d]

Substitute ,

\implies S_2=\dfrac{25}{2}[2(4) + (25-1)3] =\boxed{ 908}

Hence sum = 908 + 1 = 909

7 0
2 years ago
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