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grin007 [14]
3 years ago
8

A horizontal force of 200 N is applied to move a 55 kg television set across a 10 m level surface. What is the work done by the

200 N force on the television set?
Physics
1 answer:
vivado [14]3 years ago
3 0

Answer:

The work done is "2000 J".

Explanation:

The given values are:

Force,

F = 200 N

Mass,

m = 55 kg

Displacement,

d = 10 m

Now,

The work done will be:

⇒  Work \ done= Force\times displacement

On substituting the given values, we get

⇒                     =200\times 10

⇒                     =2000 \ J

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Answer:

  v =  7.67 m/s  for L= 1m

Explanation:

Let's use the conservation of mechanical energy, at the highest point and the lowest point

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      Em₀ = Em_{f}

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The moment of inertia of a ruler that turns on one end is

      I = 1/3 m L²

Let's replace

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      g L = 1/6 L² w²

The linear and angular variables are related

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In this case the point of interest a in strangers r = L

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Let's calculate

Assume that the length of the meter is L = 1 m

    v = √ (6 9.8 1)

   v =  7.67 m/s

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3 years ago
What is the total voltage of the circuit? (must include unit - V)
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4 0
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A stone initially moving at 8.0 m/s on a level surface comes to rest due to friction after it travels 11 m. What is the coeffici
Ivenika [448]

Answer:

Coefficient of friction will be 0.296

Explanation:

We have given initial speed of the stone u = 8 m /sec

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According to third equation of motion

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We know that acceleration is given by

a=\mu g

So 2.90=9.8\times \mu \\

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So coefficient of friction will be 0.296

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erastova [34]

Answer:

1 and 4

Explanation:

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