Answer:
Well a debtor is basically someone owing someone money, basically someone in debt. He’s telling cup head boy to take care of the people who owe him or someone else their or his money. Thats basically it.
Answer:
#include <stdio.h>
#include <ctype.h>
void printHistogram(int counters[]) {
int largest = 0;
int row,i;
for (i = 0; i < 26; i++) {
if (counters[i] > largest) {
largest = counters[i];
}
}
for (row = largest; row > 0; row--) {
for (i = 0; i < 26; i++) {
if (counters[i] >= row) {
putchar(254);
}
else {
putchar(32);
}
putchar(32);
}
putchar('\n');
}
for (i = 0; i < 26; i++) {
putchar('a' + i);
putchar(32);
}
}
int main() {
int counters[26] = { 0 };
int i;
char c;
FILE* f;
fopen_s(&f, "story.txt", "r");
while (!feof(f)) {
c = tolower(fgetc(f));
if (c >= 'a' && c <= 'z') {
counters[c-'a']++;
}
}
for (i = 0; i < 26; i++) {
printf("%c was used %d times.\n", 'a'+i, counters[i]);
}
printf("\nHere is a histogram:\n");
printHistogram(counters);
}
Answer:
nrToCheck = int(input("How many numbers do you need to check? "))
nrEven = 0
nrOdd = 0
for i in range(nrToCheck):
number = int(input("Enter number: "))
if (number % 2):
nrOdd = nrOdd + 1
print("{} is an odd number".format(number))
else:
nrEven = nrEven + 1
print("{} is an even number".format(number))
print("You entered {} even number(s).".format(nrEven));
print("You entered {} odd number(s).".format(nrOdd));
The answer is D, because it's called a back-up.