You said that she's losing 1.9 m/s of her speed every second.
So it'll take
(6 m/s) / (1.9 m/s²) = 3.158 seconds (rounded)
to lose all of her initial speed, and stop.
Answer:
Explanation:
The equilibrium mechanism for the reversible acid is catalyzed by the isomerization of non conjugated β, γ- unsaturated ketones, like 3-cyclohexanone to their conjugated α, I²- unsaturated isomers.
Oxygen of the Carbonyl group in the ketone is protonated by the acid and this is followed by the abstraction of an α- hydrogen from the protonated 3-cyclo hexanone to yield ethanol
2-cyclo hexanone can be obtained by acid catalyzation of 3-cyclohexanone isomers through the formation of it's "enol".
The most common unit is meters (m for short). It is the base unit for distance or displacement in the metric system. If you are dealing with larger distances, you might use kilometers (I'm for short) which is just 1000 meters. On the other hand, centimeter (cm) are used for small distances and are 1/100 of a meter. Another common unit is millimeters (mm) which is 1/1000 of a meter.
I would say that strong language typically reveals strong feelings: strong language would reveal desperation, or very strong feelings: weak feelings would not demand it, and would be more likely accompanied by more controlled behavior.
Answer:
1. False
2. True
3. True
Explanation:
1- False —> The relation between electric potential and electric field is given such that

Therefore, for a uniform E field, electric potential is linearly proportional to the distance.
2- True —> The electric field lines always cross the equipotential lines perpendicularly.
3- True —> In order to be a potential difference, one source of electric field is enough. The electric potential will decrease radially according to the following formula:

There is no test charge in the formula, only the source charge. Even when there is no test charge, the potential difference between points in space can exist.