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Vadim26 [7]
3 years ago
7

How can you increase efficiency of a simple machine??​

Physics
1 answer:
Blizzard [7]3 years ago
5 0

Answer:

Efficiency can be increase by using rollers in conjunction with the inclined plane. Wedge. The wedge is an adaptation of the inclined plane. It can be used to raise a heavy load over a short distance or to split a log.

Explanation:

Hope it helps

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How many distillation are there?​
anyanavicka [17]

Answer:

5

Explanation:

uifwkdhcydhebtbbfjx

4 0
3 years ago
The vertical displacement of an ocean wave is described by the function, y = A sin(ωt - kx). k is called the wave number (k = 2π
MrMuchimi

Answer:

Explanation:

a ) y = A sin(B)  ; here B is the phase of the wave which moves so that it remains constant

ωt - kx = constant

differentiating on both sides

ωdt - kdx =0

ωdt =   kdx

dx / dt = ω / k

wave velocity = ω / k

b ) ω = 14.5 rad / s ,

k = 18 rad / m

wave velocity = ω / k

= 14.5 / 18

= .805 m /s

80.5 cm / s

c )

Amplitude = A

= 9.5 m

4 0
3 years ago
Egocentrism exists during which of Piaget's stages?
Goryan [66]

Answeri believe it is the first one but not sure

Explanation:

7 0
3 years ago
Which chart provides the correct number of neutrons for each isotope of tin (Sn)?
Trava [24]
We know, Atomic mass = Atomic number + number of neutrons
Here, Atomic mass - 50 = number of neutrons [ as A.N. = 50 ]

So, According to our info. only option B can be correct, as the difference between atomic mass & number of neutrons is 50, which is atomic number of Tin (Sb)

In short, Your Answer would be Option B

Hope this helps!
6 0
3 years ago
A light bulb radiates 110 nW of single-frequency sinusoidal electromagnetic waves uniformly in all directions. Calculate the ave
krek1111 [17]

Answer:

The intensity of the light from the bulb would be

3.501 x 10^{-6} W/m^{2}

Explanation:

Given

The Power = 110 n W = 110 x 10^{-9} W

the distance r = 50 mm = 50 /1000 = 0.05 m

The intensity can be obtained with the relationship below;

I = Power/area ......1

The area of the sphere would be used in this case since the bulb is spherical;    A=4πr^{2}

Putting it into equation 1, we have;

I = P/ 4πr^{2}

I =  110 x 10^{-9} / 4 x π x 0.05^{2}

I = 3.501 x 10^{-6} W/m^{2}

Therefore the intensity of the light from the bulb would be

3.501 x 10^{-6} W/m^{2}

6 0
4 years ago
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