The period is the time it takes any repeating process
to complete one cycle. You just told us what it is for the
pendulum . . . 6 seconds.
The frequency is the reciprocal of the period. For the pendulum,
that's
1 / (6 sec) = (1/6) per second = 1/6 Hertz .
Answer:
we would have no oxygen and barely any water.
The Porter does no work because the force applied is perpendicular to the displacement
Explanation:
The work done by a force applied to an object is given by:
where
F is the magnitude of the force
d is the displacement
is the angle between the direction of the force and the displacement of the object
From the formula, we notice that:
- The work done is maximum when the force is parallel to the displacement (because )
- The work done is zero when the force is perpendicular to the displacement (because )
In this problem, Porter is carrying the suitcase: this means that the force he is applying is upward (to balance the weight of the suitcase, pulling down), while the displacement is in the horizontal direction: therefore, force and displacement are perpendicular, so the work done is zero.
Learn more about work:
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speed = 86km/hr
= 86000/3600
= 23.889m/s
time = 4.6s
acceleration = 23.889/4.6
a = 5.19m/s^2
The solution for this problem is:
v = sqrt(T/µ) where T = m*g = 4*g and µ = 0.0055/2.5 = 0.0022kg/m
Now L = 2 m
For a string the frequencies are n*v/2L
so n*v/2L = 64 and (n+1)*v/2L = 80
Now eqn 2 divided by eqn 1 yields (n + 1)/n = 80/64 = 1.25
=> 1.25 n = n + 1 or .25n = 1 or n = 4
now subbing back into eqn 1 we have 4*v/2L = 64 or v = 32*L = 32*1.9 = 60.8
So 60.8= sqrt(1.1*g/0.0022)
so 1.1*g = 60.8^2*0.0022 = > g = 60.8^2*0.0022/1.1 = 7.39 m/s^2